Recent content by vicsic

like x(t)=changeinD/change in v

Would that be t=d/v=d/v??

Question: A car is initially 4.0km/h south of a gas station and is moving at a constant speed of 55km/h due north. A truck is initially 6.0km north of the gas station and is moving at a constant speed of 45km/h due south. How far are the vehicles from the gas station when they pass each other...

I am currently in high school and am decided what career to pursue. I shadowed a medical physicist for a day and found it to be quite interesting. After doing more research I discovered that usually an undergraduate degree in physics is needed to pursue further studies in med phys. I am taking...

thanks i got the answer! :)

Got the answer! 1.4m=vi(0.20)+1/2(-9.81)(0.20)^2 1.4m=vi(0.20)-0.1962 1.5962=vi0.20 vi=7.981 m/s then plugging it back in d=vi(t)+1/2at^2 d=7.981(0.20)+1/2(9.81)(0.20)^2 d=1.7924 d=1.8m thanks for the help :)

1.4m=vi(.20)+1/2(9.81)(0.20)^2 1.4=vi(0.20)+.1962 1.2038=vi(0.20) vi=6.019m/s

So i found that the initial velocity is 6.019 m/s now how does that lead me to how far above the window the rock will travel?

I am still a bit confused with the x's u are using in your formula. We were given the formula d=vi(t) + 1/2at^2 how did u get all of those x's into it and 0's for the x's thanks for all the help!

car 1- vi=0 m/s a=5.00 m/s^2 Truck v=25.0 m/s assuming the distances are the same at the beginning distance would equal zero as they are stopped using the formula d=Vi(t)+1/2at^2 0=0t+1/2(5.00)t^2 0=1/2(5.00)t^2 0=5.00t^2 0=t^2 t=0 plug that back into the formula...

When I solve for t it become zero, therefore the distance becomes zero which is impossible. any other suggestions

Homework Statement A rock is thrown up past a window. The rock requires 0.20 s to completely pass by the 1.4 m window calculate the height above the window the rock would travel. Homework Equations D=vf(t) -1/2at^2 The Attempt at a Solution I have tried using the acceleration as...

Homework Statement A car is waiting at a stoplight. Just as the light turns green and the car starts to accelerate, a truck passes at a constant velocity in the next lane. The truck passes at a velocity 25.0 m/s while the car accelerates 5.00 m/s^2 both in the same direction, Calculate the...