Recent content by webren

  1. W

    Why Is the Center of Gravity Calculation Resulting in Negative Coordinates?

    I understand a lot better. Thank you. There is another similar problem where it shows an L-shaped ruler and each side's length. There is no mass given, so I assumed the center of gravity of the scenario is the sum of the coordinates multiplied by the area, divided by the total area of the...
  2. W

    Why Is the Center of Gravity Calculation Resulting in Negative Coordinates?

    Ah, I think I see. So is dividing not necessary at all for this kind of problem?
  3. W

    Why Is the Center of Gravity Calculation Resulting in Negative Coordinates?

    Here is my work for the x coordinate of the center of gravity: The sum of the coordinates multiplied by their respective masses are: (5kg)(0) + (3kg)(0) + (4kg)(3m) + (8kg)(x) = 0. I know I need to find x, so the equation becomes: (8)(x) + 12 = 0 The sum of all the masses are (5 + 3 + 4...
  4. W

    Why Is the Center of Gravity Calculation Resulting in Negative Coordinates?

    Hello, I with this problem, I am getting the correct answer, but I do not know why the book's answer is negative: "Consider the following mass distribution: 5.00 kg at (0,0) m, 3.00 kg at (0, 4.00) m, and 4.00 kg at (3.00, 0) m. Where should a fourth object of mass 8.00 kg be placed so...
  5. W

    Solving Statics Ladder Problem: Understanding the Use of Trigonometry and Torque

    I understand. Both of you explained it very well. Thanks.
  6. W

    Solving Statics Ladder Problem: Understanding the Use of Trigonometry and Torque

    Hello, I am having a little trouble with this statics problem: "A 15.0 m uniform ladder weighing 500 N rests against a frictionless wall. The ladder makes a 60 degree angle with the horizontal. (a) Find the horizontal and vertical forces the ground exerts on the base of the ladder when an...
  7. W

    Why Do Equivalent Formulas for Radial Acceleration Yield Different Results?

    Haha, okay. Thanks for clearing that up. Yes, in answering my direct question, what you said makes perfect sense.
  8. W

    Why Do Equivalent Formulas for Radial Acceleration Yield Different Results?

    My professor has said that radial and centipetal acceleration/force are the same thing. Or is it just force that is equivalent? You said radial acceleration is alpha, but alpha is used throughout the chapter as angular accleration. Is angular and radial acceleration the same thing then...
  9. W

    Why Do Equivalent Formulas for Radial Acceleration Yield Different Results?

    Hello, I was able to solve this problem fine, but I had a question about it: "A disk 8.00 cm in radius rotates at a constant rate of 1200 rev/min about its central axis. Determine (a) its angular speed, (b) the tangential speed at a point 3.00 cm from its center, (c) the radial...
  10. W

    How Does Rocket Propulsion Calculation Work with Changing Mass?

    Hello, I am not understanding how the book got it's answer from the supplied rocket propulsion example. "A rocket moving in free space has a speed of 3.0 x 10^3 m/s relative to the Earth. Its engines are turned on, and fuel is ejected in a direction opposite the rocket's motion at a speed...
  11. W

    Solving Power Cable Question - Part (b)

    Ah, of course. I figured it out. Thank you.
  12. W

    Solving Power Cable Question - Part (b)

    Hello, I solved the first part of this problem, but I am a little stuck with finding the second part, which deals with power. "A skier of mass 70.0 kg is pulled up a slope by a motor-driven cable. (a) How much work is required to pull him a distance of 60.0 m up a 30 degree slope (assumed...
  13. W

    Motion In the Presence of Resistive Forces

    I don't know why I was thinking of m(v^2/r). It's probably from doing circular motion problems all day. I understand your statements regarding the problem and I have solved it. There is another problem that is in the same category that I don't quite understand as well. "Calculate the...
  14. W

    Motion In the Presence of Resistive Forces

    Hello, I am having a difficult time getting far into solving this problem: "A small piece of Styrofoam packing material is dropped from a height of 2.00 m above the ground. Until it reaches terminal speed, the magnitude of its acceleration is given by a = g - bv. After falling 0.500 m...
Back
Top