Recent content by wee00x

But then how would that be calculated?

The energy needed to strip all three electrons from a Li(g) atom was found to be 1.96*10^4 kJ/mol. The first ionization energy of Li is 520 kJ/mol. Calculate the second ionization energy of Lithium atoms (the energy required for the process) Li+(g) ---> Li+2 + e- Equation: frequency =...

Okay, thank you for helping me clear that up! So He- is larger than Ne because although they are on the same energy level, He- has less of an electrostatic attraction, being that it has less protons, and so the electrons are not bound as tightly to the nucleus as they would be with Ne.

I imagine that the helium ion would be smaller... because it has less protons than lithium does... but there is also the fact that since there are less protons than lithium, there is less electrostatic attraction, and so the electrons are not held in as close for the helium ion. I feel that this...

neon would be smaller than lithium. Does this mean that He- would be larger than neon?

So would the He- be larger than the Ne atom, since it would be on the some energy level, but farther to the left on the periodic table?

Well as you go down the periodic table, the size of the atoms will increase because of the addition of higher energy levels, increasing atomic radius. However, when you go across the periodic table to the right, the electrostatic force between electrons causes them to become more compact and...

Oh I see.. Well I understand the trends but I don't understand why it is that way. Do you have a explanation that can clear it up??

Does anyone know the answer to this? How does the He- ion compare in size to that of the Ne atom?? How can you tell which one is bigger?

I understand that He- is larger than He, but I don't know which is bigger between He- and Ne.. please help??

The outer electron (valence electron) of an alkali atom may be treated in an approximate way, as if it were in a hydrogenic orbital. Suppose that one takes the quantum number for the valence electron to be 2, 3, 4, 5, and 6, respectively, for Li, Na, K, Rb, and Cs. What values of the...

indefinite integral of sin^2(ax)dx = .5x - .25asin(2ax) that is the second formula. and I tried working it out but I couldn't get L to cancel out.. i just got an ugly answer...

I am confused as to what I use the second formula for... How do I find the probability of the particle being located in the region bounded by x=l/4 and x=l/2? How do i get an actual value for this since L is being used, and not a real number?

The normalized wave function for a particle in a 1D box in which the potential energy is zero between x= 0 and x= L and infinite anywhere else is normalized wave function = sqrt(2/L)*sin(npix/L) What is the probability that the particle will be found between x= L/4 and x= L/2 if the...