Recent content by wellY--3

hi, I understand how to use the limiting chord process to find the gradient of a curve, but how do you do it when they ask for a certain point on the curve. for example find the gradient using the limiting chord process on the curve y=x^2 +2 at the point (1,3) If you sub the points into...

oh yer 7.44*10^(-2) sorry so if i had to work out the number of moles of Mg and O seperately it is just 7.44*10^(-2) mol? so the ratio n(Mg0:n(O) would be 1:1? so then that makes the empirical formula just MgO?

when you have to work out the amount of moles in 3 grams of magnesiun oxide (2 grams are magnesium) would you go 0.3 divided by 40.31? then the answer is 7.44x10^-3 so that means that's the nuymber of moles of magnesium and also the number of moles of oxygen. So if u had to find the ratio of...

so c =-12x is that right?

what?? and put in the original what

A family of quadratic functions passes through the points (3,0). Find the family of quadratic functions err i have no idea hwo to do it except substituting those values in ... 0=9a+3b+c what does it meant the family of quadratic functions?

i thought c was always the hypotenuse ...so b^2=c^2-a^2

ok ok so then it equals c^2+a^2/ca I still don't see how the top can equal b^2

ABC is right angled at B. Prove that tanA+tanC=b^2 / ac Ok so far I've got that tan A= a/c and tanC=c/a and then when i try to add those together i get (c^2)(a^2)/ac , but how can (c^2)(a^2) = b^2 all I've thought of is pythagorus's theorem. But for it to equal b^2, a^2 has to be...

ooooooook so... 1. b=square root of 40 2 b is greater than square root of 40 3. b is less than square root of 40 is that right?

b has to be a real number but how can you work it out when there are two unknowns .. x is unknown and so is b

1. A quadratic fraction is of the form f(x)= 2x^2+bx+5 Find the values for b where the graph of f(x): 1.just touches the x-axis 2. has two x-intercepts 3.does not cut or touch the x-axis I've tried using the quadratic formula but i have no idea how to do it when there are two unknowns...