Recent content by xts

You are right: at the same temperature both emits the same power. But the hollow one has smaller heat capacity, so - emitting the same power it cools faster.

So now I have no idea what do you mean by "standard method". There are lots of methods to measure R.I. which may be used for liquids of both higher and lower R.I. than the one of glass.

Refractive index of mercury? It seems to be too opaque to have well defined refractive index (at least if you take r.i. in its classical meaning).

No. Just imagine the body which emissivity is non-zero only in some narrow span (e.g. vapour of Sodium). Regardless of temperature its maximum of emission is always yellow.

There is no such thing as 'force' in modern, quantum-mechanics, approach. In naive Newton's mechanistic model of light you may treat photon as a snooker ball, but not at the flat table, but rather on the one with one half lifted a bit comparing to other, so the photon receives impulse...

@A.T. torpedo itself is affected by Coriolis force in the same manner as a projectile moving in vacuum. Let's say (we are on Northern hemisphere) to the right. But the water surrounding it flows around in opposite direction. The water is affected by Coriolis force to its right, which causes...

Coriolis effect is even stronger for underwater object than for the one moving in vacuum. But it still is negligible when compared to other forces disturbing the torpedo trajectory (water currents, waves, imperfect geometry, etc.) so since WWI (when torpedos reached range bigger than 1000...

Good luck! You may want to make a plot of the computed (fitted) trajectory against raw data to see if your idealisation (no friction) really works. If you find some systematic discrepancy, then you can try multiple fits for partial data, e.g. points 1-9 gives you estimation of trajectory...

You must assume that trajectory is of the form:x(t)=v_{x0}t+x_0,\quad y(t)=gt^2+v_{y0}t+y_0, then express your distances as a function of (x,y), take 5 points and solve those 5 equations system to obtain (g,v_{x0},v_{y0},x_0,y_0) or (better) take more points and perform least square fit over...

Just take (for every time) several consecutive measurements (a bit earlier and a bit later) from both detectors and perform least square fit of second-order trajectory to estimate the position at the given time.

Yes. You may treat elliptically polarized beam as a linear combination of vertical and horizontal waves, shifted in phase by 90^\circ. The vertical part will be reflected in one direction, the horizontal one in another in your cube.

Water has low compressibility, but the pipe must be ellastic (not quite predictably for plastic/rubber pipes), it suffers from ageing, water loss due to leaks and vapourisation, then you have thermal effects, and lots of others absolutely unpredictable. Believe me - that is the worst possible...

Forget the idea! You would have equip all the legs not with tubes (which get flattened under pressure), but rather with pistons with well knows area. Other problem is that such suspension for your bed is not stable - if the weight is not distributed centrally, some legs would totally collapse...

If it is a good mirror (reflecting nearly all light) it won't glow - it's emission/absorption coefficient is close to zero. And it will still reflect the light as previously. The only cause to change reflection coffeicient may be changes to mirror surface, but, as I guess it was not your...

You may neglect surface tension and similar forces. It counts for few milimeter droplets, but not for a large body. If your body is not rotating (or the rotation is slow), you may assume spherical symmetry. You may probably assume that the density \rho is uniform. So now the gravity on the...