Recent content by Yahaira.Reyes

wouldn't I need to calculate the time ? All of the equations require time.

A connon, located 60 m from the base of a vertical 25.0m tall clift, shoots a 15 kg shell at 43.0 degrees above the horizontal toward the cliff. A) what must the minimum muzzle velocity be for the shell to clear the top of the cliff? B) The ground at the top of the cliff is level, with a...

Are there any formulas? And are you calculating the equillibrium constant? Please re-write the question clearer with units. I will try to help you o:) I think the answer to the first question is because strong acids such as HCL and HF dissociate completely in water making them strong...

i know i couldn't believe it! I was so frustrated trying the problem out over and over. I lauphed so hard when i figured it out lolz... I thought it was such a hard problem, turned out pretty easy

a ha! i just saw my mistake! But i will show you my calculations that i just re-did \theta_{AB}= arccos[ -10/ (4.58* 3.16)] = arccos(-10/ 14.47) = 133.7 Thanks a lot!

sorry if i posted it three times. It is my first time using this program. magnitude of a= \sqrt{2^{2}+ 1^{2}+ 4^{2}}= 4.58 Magnitude of b= \sqrt{-3^{2}+ 1^{2}}= 3.16 and the vector A * the Vector B gives me -10

Homework Statement Let vectors \vec{A}=(2,1,-4) \vec{B}=(-3, 0, 1), and \vec{C}= (-1, -1, 2) . Calculate the following: What is the angle\theta_{AB} between \overline{A} and \overline{B} ? Homework Equations \vec{A} * \vec{B}= magnitude of A * Magnitude of B * Cos\theta...