How Do You Calculate the Angle Between Two Vectors?

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Homework Help Overview

The discussion revolves around calculating the angle between two vectors, specifically vectors A and B, given their components. The original poster presents their calculations and seeks assistance in verifying their approach and results.

Discussion Character

  • Exploratory, Mathematical reasoning, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the calculation of vector magnitudes and the application of the cosine formula to find the angle between the vectors. There is an emphasis on verifying arithmetic and ensuring correct application of the formula.

Discussion Status

The conversation has progressed with the original poster identifying a mistake in their calculations after initial attempts. Some participants have provided encouragement and requested further details on the calculations to assist in clarifying the process.

Contextual Notes

There are indications of confusion regarding the posting frequency, with the original poster apologizing for multiple submissions. The discussion reflects a learning environment where participants are encouraged to show their work for better assistance.

Yahaira.Reyes
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Homework Statement



Let vectors [tex]\vec{A}[/tex]=(2,1,-4) [tex]\vec{B}[/tex]=(-3, 0, 1), and [tex]\vec{C}[/tex]= (-1, -1, 2) .
Calculate the following:

What is the angle[tex]\theta_{AB}[/tex] between [tex]\overline{A}[/tex] and [tex]\overline{B}[/tex] ?

Homework Equations



[tex]\vec{A}[/tex] * [tex]\vec{B}[/tex]= magnitude of A * Magnitude of B * Cos[tex]\theta[/tex]

magnitide of X= [tex]\sqrt{a^{2}+b^{2}+C^{2}}[/tex]

The Attempt at a Solution



magnitude of A= 4.58
Magnitude of B= 3.16

[tex]\theta[/tex]=arccos[( A * B)/ magnitude of A * magnitude of B)

I tried that but the incorrect answer. Maybe i did the arithmetic wrong. Please Help..
 
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I can't tell you if you did the arithmetic wrong if you don't show your calculations...

Also, it seems you posted this problem in the forum 3 times. Please do not flood the forum with repeat posts.
 
sorry if i posted it three times. It is my first time using this program.

magnitude of a= [tex]\sqrt{2^{2}+ 1^{2}+ 4^{2}}[/tex]= 4.58

Magnitude of b= [tex]\sqrt{-3^{2}+ 1^{2}}[/tex]= 3.16

and the vector A * the Vector B gives me -10
 
Last edited:
OK, you calculations for the magnitudes are correct. Can you show me what you get for [tex]\theta[/tex] and the full calculation involved?

I ask because you have the correct formula, so I think the error is probably in your calculation somewhere.
 
a ha! i just saw my mistake! But i will show you my calculations that i just re-did


[tex]\theta[/tex][tex]_{AB}[/tex]= arccos[ -10/ (4.58* 3.16)]

= arccos(-10/ 14.47)
= 133.7

Thanks a lot!
 
Yahaira.Reyes said:
a ha! i just saw my mistake! But i will show you my calculations that i just re-did


[tex]\theta[/tex][tex]_{AB}[/tex]= arccos[ -10/ (4.58* 3.16)]

= arccos(-10/ 14.47)
= 133.7

Thanks a lot!

;-)

I can't tell you the number of times I begin to spend the time typing up a problem here, and then all of a sudden I figure out the answer to my question.
 
Good Job!
 
i know i couldn't believe it! I was so frustrated trying the problem out over and over. I lauphed so hard when i figured it out lolz... I thought it was such a hard problem, turned out pretty easy
 

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