Recent content by yusukered07

Yeah... That's the process I've made... Then I integrate them with respect to t and evaluate from 0 to 2

I didn't pretend that I know the answer. Here is my solution to the problem I posted. To letter (a). A\cdot B = 2t^{3} + 6t^{2} - 6t Taking its integral with respect to t from 0 to 2 will give an answer of 12. To letter (b). A\times B = -6t^{3}i + [2t^{2} (t -1) - 6t^{2}]j - 2t^{4}k...

I evaluate the values of A\cdot B and A\times B first. Then integrate the both with respect to their limits.

The solution I've made is not complicated. You try first to evaluate the vectors and then take the integral of them.

In an affine plane of order n, prove that each line contain exactly n points

http://www.quickmath.com/

is there any proof you can show?? that's the question..

So, will you help me to make a proof?

What is i there? n is normal line, I think

Thanks! I've got the answer..:smile:

Sorry for giving a wrong problem...

Homework Statement If A(t) = t i - t2 j + (t - 1) k and B(t) = 2t2 i + 6t k, evaluate (a) \int^{2}_{0}A \cdot B dt, (b) \int^{2}_{0}A \times B dt. Homework Equations The Attempt at a Solution Help me please because I don't know how to solve this problem. Thanks! Looking...

If A(t) = t i - t2 j + (t - 1) k and B(t) = 2t2 i + 6t k, evaluate (a) \int^{2}_{0}A \cdot B dt, (b) \int^{2}_{0}A \times B dt.

Homework Statement \int_{S}\int n dS = 0 for any closed surface S. Homework Equations The Attempt at a Solution I can't solve this because I don't have any idea in Vector intregrals.

If A(t) = t i - t2 j + (t - 1) k and B(t) = 2t2 i + 6t k, evaluate (a) \int^{2}_{0}A \cdot Bdt , (b) \int^{2}_{0}A \times B dt.