Thanks guys, the answer WAS 140 degrees :smile: . I thought I had tried that answer before I tried 220, but I only tried 220 Thanks for making my physics experience a little better :rolleyes:
At least I understand why I got that answer now
Well I am not sure what I did wrong because neither 140 or 220 degrees is correct. Is the equation supposed to be F_n_e_t_x = -F_1 + F_2\cos(\theta)? Hopefully someone can show me where I went wrong
Yes, I believe that is right. However, I tried inputting 140 and it is incorrect. I am unsure if F_1 is actually going at 180 degrees. It only says it is going in the negative x direction? Also, I am unsure if I am setting up the equation correctly, and also if I am supposed to use...
I need help with this problem (my work is at the bottom):
http://img96.imageshack.us/img96/9823/physicsquestiondd9.jpg
Here is what I tried:
a_x from graph = 3 m/s^2
Fnetx = m* a_x
F_n_e_t_x = 3.9 N
F_n_e_t_x = -3 + F_2*\cos(\theta)
6.9 = 9.0*\cos(\theta)
\cos(\theta) = 0.7667
\theta =...