Recent content by zealeth

The instantaneous center is at the point where it contacts the ground, or in this case, point C. I don't know how I would relate this to the velocity of the mass since the mass's instant center is changing as the disk rolls.

Homework Statement The disk in Figure 3.30 of radius R rolls without slipping with constant angular velocity Ω. Carved inside the disk is a slot and a mass moves inside the slot. Denoting the position of the mass inside the slot by s, calculate the velocity and acceleration of the mass as a...

Homework Statement The tank shown in the figure is filled with water and fastened to the ground. There is a small opening on top of the semi-spherical part of the tank. a) What is the magnitude of the horizontal force on the screws? Explain using a free body diagram. b) Consider the proper...

Isn't that what I did the first time, just with the mistake of me writing voltage instead of current? Just tried that, VOC = 35V which when plugged into the following equations gives me the right answer. However, I've noticed that this is very close to the real part of the Vt value I obtained...

Thanks for the reply. Sorry, I meant to say that was the *current* across the capacitor, not the voltage. So now repeating the same method starting from ISC while combining R and Z: R||Z = 46*j14/(46+j14) = 3.9+j12.8 R||Z + C = 3.9+j12.8 -j10 = 3.9+j2.8 ISC = V/R = 10/(3.9+j2.8) =...

Homework Statement Consider the circuit shown in the figure below. Suppose that R = 46Ω and Z=j14Ω. Determine the maximum average power that can be delivered to the load if the load is pure resistance. Note that the voltage source magnitude is given as Vmax, not VRMS Homework Equations j =...

That might be it, I had never seen an opamp shown with the power supply pins yet. So doing this with V+ = V- = 0, I have, Node a: \frac{V_o - V_a}{100k}+\frac{V_b - V_a}{20k} = \frac{V_a - V_g}{5k} + Va*(jωC) \frac{V_o - V_a}{100k}+\frac{0 - V_a}{20k} = \frac{V_a - 1}{5k} +...

I'm not sure what you're getting at here. The voltage on the + terminal is -5V which is given, so the difference between the terminals is -10V. However, I don't see what the positive terminal has to do with the problem.

I believe I set it up the way my professor intended, as this was the method we used in class. He also specifies the node "at" the inverting input, rather than something along the lines of "node b is the inverting input."

Because it is directly connected to the 5V terminal of the op amp. Yes, that was a typo. I fixed it now.

Homework Statement The op amp in the circuit seen in the figure is ideal. Find the steady-state expression for vo(t). vg = 1cos(106t) V. Express your answer in terms of t, where t is in microseconds. Enter the phase angle in radians. Hints: (1) Let the node above the capacitor be Node a, and...

Homework Statement Compute values for R and C such that the total series impedance Z=500\angle(-36.1o) when f=10kHz. Homework Equations ω=2\pif KVL ZC = -j*(1/(ωC)) = 1/(jωC) where j=\sqrt{-1} The Attempt at a Solution Seems like a pretty straightforward problem, I seem to...

The circuit I've shown is what was given with the problem statement. And no, I do not know what di/dt is at t=0+.

Homework Statement In the circuit in the following figure, the resistor is adjusted for critical damping. The initial capacitor voltage is 15 V, and the initial inductor current is 6 mA. Find the numerical value of R. Find the numerical values of i immediately after the switch is closed...

Homework Statement The current in a 28mH inductor is known to be −10A for t≤0and (−10cos(400t)−5sin(400t))e^(−200t) A for t≥0. Assume the passive sign convention. At what instant of time is the voltage across the inductor maximum? What is the maximum voltage? Homework Equations v(t) =...