Recent content by zinc79

Hey, thank you for replying. See, what I forgot to mention was my perspective on the parallel plate capacitor, which yes, has a uniform electric field. There is NO change in the p.d. as we move from one plate to the other, so shouldn't dV/dx become zero?

A bit of a problem. My book teaches me that E = -(dV/dx), where E is the electric field strength, V is the electric potential, and x represents displacement. But, it also suggests along with the above formula that E = -(V/d) and displays a circuit with a battery of p.d. V and two parallel...

Homework Statement A uniform rod AB, of length (2a) and mass (m) has a particle of mass (0.5m) attached to B. The rod is smoothly hinged at (A) to a fixed point and can rotate without resistance in a vertical plane. It is released from rest with AB horizontal. Find, in terms of (a) and (g), the...

realization First of all, thanks for replying. Secondly, you seem to be treating the centroid and center of mass separately. Are they not the same? Please clarify me on this. "Symmetric relative to the centroid". What do you mean by this? I don't see any form of symmetry, like in the...

I've been having some confusions regarding the centroid coordinates of triangles. I've been taught that the centroid of a triangle lies at 1/3rd of the perpendicular distance from any selected base to the corresponding top point of the triangle. I tried to use this shortcut to find the...

I see, so although the force has increased, the radius still increases? What's with all this dependence and independence anyway? I never seem to make sense of it, or make it out on my own. If you hadn't told me that the angular velocity remains the same (which I didn't know), and if I was using...

Recently, in a test, I had a question involving a magnetic field and an electron. I've attached the diagram. The "X" denote the magnetic field, moving inwards. So, there's a uniform magnetic field, moving into the plane of the picture, and there's an electron passing over that plane with its...

I get you Doc Al, but wikipedia says that "Gravitational potential energy is the work of gravitational force", and well, it is a popular source... I'm still confused...

Hello. I'm new. I was looking around on the web a bit to find an answer to my problem, and I came across these forums. Gravitational force = -GMm/(r^2) Gravitational force between a small mass (m) and the Earth (M) is zero at a distance of infinity. Any distance smaller than infinity gives...