A bit of a problem. My book teaches me that E = -(dV/dx), where E is the electric field strength, V is the electric potential, and x represents displacement.(adsbygoogle = window.adsbygoogle || []).push({});

But, it also suggests along with the above formula that E = -(V/d) and displays a circuit with a battery of p.d. V and two parallel metal plates of distance (d) from each other.

My question is, HOW did E = -(dV/dx) become E = -(V/d)??? The former formula, proven via differentiation, says that the electric field strength is negative of thepotential gradienti.e. rate of change of electric potential with respect to the displacement. Thenhowdoes this transform into the electric field strength simply being equal to the negative of the ratio of the potential difference to the distance? It makes no sense to me!

And yet, I've seen the latter formula being used in practice questions.

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# Electric field strength and potential gradient

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