I'm still stuck at finding the momentum of the electron. I know it's going to have 50 000ev of Kinetic Energy, but I'm not sure how to relate it to momentum.
Homework Statement
If the maximum energy transferred to an electron during Compton Scattering is 50KeV, what is the wavelength of the incident photon?
Homework Equations
\lambda' - \lambda_{o} = h/(Me*c)(1-cos\theta)
The Attempt at a Solution
We know that the maximum energy...
Well, E = hc/\lambda
From de Broglies wavelength equation,
\lambda = h/p
so here \DeltaE=\Deltapc
So to find the uncertainty in position, I have \Delta\lambda, change that to \DeltaE. From there I can get \Deltap, and
\Deltax = h/4\pi\Deltap
Where \Deltax is the minimum...
Homework Statement
A wavelength measurement gives Lambda= 6000 x 10^-10m with an accuracy of one part in a million. What is the minimum uncertainty in the position of the photon?
Homework Equations
deltaP*deltaX > h/4pi
p = h/lambda
The Attempt at a Solution
In order to solve...