Is There a General Formula for this Partial Fraction Function?

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A general formula for the partial fraction decomposition of the function 1/((ax_1+1)(ax_2+1)...(ax_L+1)) is sought, specifically in the form of c_1/(ax_1+1) + c_2/(ax_2+1) + ... + c_L/(ax_L+1), where c's are constants. The discussion clarifies that 'a' is treated as the variable while the 'x's are constants, meaning the c's are determined by the values of the x's. The complexity increases with larger values of L, but a general solution expression has been found. The conversation emphasizes understanding the relationship between the variables and constants in partial fraction problems.
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Hello,

Is there any general formula for the partial fraction of the following function:

\frac{1}{(ax_1+1)(ax_2+1)\cdots (ax_L+1)}

I can work for L=3, but it get involved for larger L!

Thanks in advance
 
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Ok... from what I've understood, you want write

\frac{1}{(ax_1+1)(ax_2+1)\cdots(ax_L+1)}

as

\frac{c_1}{ax_1+1}+\frac{c_2}{ax_2+1}+\cdots+\frac{c_L}{ax_L+1}

where the c's are constants. My question is, what is the variable the c's must be independent of? a or x?
 
coelho said:
Ok... from what I've understood, you want write

\frac{1}{(ax_1+1)(ax_2+1)\cdots(ax_L+1)}

as

\frac{c_1}{ax_1+1}+\frac{c_2}{ax_2+1}+\cdots+\frac{c_L}{ax_L+1}

where the c's are constants. My question is, what is the variable the c's must be independent of? a or x?

a is a constant, and x's are the variables.
 
coelho said:
Ok... from what I've understood, you want write

\frac{1}{(ax_1+1)(ax_2+1)\cdots(ax_L+1)}

as

\frac{c_1}{ax_1+1}+\frac{c_2}{ax_2+1}+\cdots+\frac{c_L}{ax_L+1}

where the c's are constants. My question is, what is the variable the c's must be independent of? a or x?

Problems involving partial fractions usually have one variable and many constants. From the appearance of your expression, I assume a is the variable and the x's are constants. In that case the c's will be determined by the x's.
 
mathman said:
Problems involving partial fractions usually have one variable and many constants. From the appearance of your expression, I assume a is the variable and the x's are constants. In that case the c's will be determined by the x's.

yes, right. a is the variable and x's are the constants. I got the general solution expression.

Thanks
 
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