Imafungi said:
Where is the evidence of his proof though, is it not just an argument like my argument, it seems like circular logic, I can call my argument a proof and say it shows that such an interpretation of entanglement works, proving Bells proof wrong.
Calling something a "proof" doesn't make it one.
Since as it appears you have caught me red handed, why not work to my weaknesses and prove me wrong as plain and simply as possible? Or do you need bells and whistles and smoke and mirrors to make your beliefs right?
Bell's theorem shows that your belief is WRONG. It's not showing that any particular alternative belief is right. What he showed was wrong was the belief that once the particles separate, it's predetermined what the result of every possible measurement will be. That cannot possibly be the case.
To see this, you really have to look at and understand the mathematics. Only the very simplest theories can proved right or wrong without using any math, and quantum mechanics is certainly way beyond that.
Ok, I tried to follow your math and I cant. So to just use two created entangled particles. When one is measured spin up, and the second is measured spin down. What is any experimental evidence that; When two entangled particles are created (before any measurement/observation) one of the entangled particles exists in a spin up state, and the second exists in a spin down state. What is the experimental evidence that says that physically is impossible?
What you don't seem to understand about electron spin is that it's not absolutely spin-up or spin-down. It's measured to be spin-up or spin-down relative to a particular direction. For example, let's pick three different directions as follows: Let direction A be straight up. Let direction B be at a 120 degree angle from A. Let direction C be in the same plane as A and B, but 120 degrees away from each.
Alice and Bob both use the same three directions. Every time an entangled pair is produced, Alice randomly picks one of the three directions to measure the electron's spin, and Bob randomly picks one of the three directions to measure the positron's spin. What they find, through many many trials, is the following:
- No matter which direction Alice chooses, she gets spin-up half the time and spin-down half the time.
- Same for Bob.
- If Alice and Bob pick the same direction, they ALWAYS get the opposite result.
- If Alice and Bob pick different directions, then 1/8 of the time, Alice gets spin-up and Bob gets spin-down. 1/8 of the time, Alice gets spin-down and Bob gets spin-up. 3/8 of the time, they both get spin-up. 3/8 of the time, they both get spin-down.
So it's not as simple as "Alice and Bob always get the opposite result". That's what happens when they both choose the same direction, but that's not what happens when they choose different directions. So your idea that it's predetermined that Alice will always get the opposite of Bob is wrong. It's more complicated than that.
A more sophisticated model is this: Every correlated pair has an associated label. One of 8 possible labels:
- ABC
- AB\bar{C}
- A\bar{B}C
- A\bar{B}\bar{C}
- \bar{A}BC
- \bar{A}B\bar{C}
- \bar{A}\bar{B}C
- \bar{A}\bar{B}\bar{C}
A in the label means that Alice will measure spin-up in that direction, and Bob will measure spin-down. \bar{A} in the label means that Alice will measure spin-down in that direction, and Bob will measure spin-up. Similarly for B, \bar{B}, C \bar{C}.
So your idea that the outcomes are fixed ahead of time can be generalized by these labels: The outcome is fixed for every choice of measurement direction, (although different directions can have different results).
So to complete this hidden variable model, you need 8 numbers:
P(ABC), P(AB\bar{C}), ... giving the probabilities of each of the 8 labels.
To match the predictions of quantum mechanics, the probabilities have to add up correctly.
There is no possible choices for those 8 numbers that reproduce the predictions of quantum mechanics. There is no way to see that, other than to do some math. We could simplify it
by assuming certain symmetries, which is that swapping A and B shouldn't change anything. Swapping A and C shouldn't change anything. Swapping spin-up for spin-down shouldn't change anything. So with those assumptions, there are only two numbers:
P(ABC) = P(\bar{A}\bar{B}\bar{C} = x
P(AB\bar{C}) = P(A\bar{B}C) = P(\bar{A}BC) = P(\bar{A}B\bar{C} = P(\bar{A}\bar{B}C) = P(A \bar{B}\bar{C}) = y
To reproduce the predictions of quantum mechanics, it must be that
P(ABC) + P(AB \bar{C}) = x+y = 1/8
2x + 6y = 1 (because the probabilities have to add up to one).
These two equations have the solution:
y = 3/16
x = -1/16
Since probabilities have to be positive, this is ruled out. So there are no possibilities left. Using deterministic hidden labels can't work.