Understanding Wave Graphs: 4t & 30° Phase Angle

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SUMMARY

The discussion focuses on the sinusoidal wave equation Vs = Vm*sin(4t + 30°) and its components, specifically the impact of the angular frequency (4t) and the phase angle (30°) on the graph of the wave. The angular frequency determines the number of wavelengths within a given period, while the phase angle represents a horizontal shift of the wave. The conversation emphasizes the importance of understanding the relationship between frequency, period, and phase in wave analysis.

PREREQUISITES
  • Understanding of sinusoidal wave equations
  • Knowledge of angular frequency and its calculation
  • Familiarity with phase angles and their graphical representation
  • Basic concepts of frequency and period in waveforms
NEXT STEPS
  • Study the relationship between frequency and period in waveforms
  • Learn about the effects of phase shifts on sinusoidal graphs
  • Explore the mathematical principles behind angular frequency calculations
  • Review Calculus I concepts related to function transformations, specifically f(cx) and f(x + c)
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Students, educators, and professionals in physics, engineering, and mathematics who seek to deepen their understanding of wave behavior and analysis.

Maxwell
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Lately, I have been trying to get a deeper understanding of a few concepts, and I was trying to analylize a wave I found in my textbook:

I know the sinusoidal equation is:

Vs = Vm*sin({\omega}t + {\phi})

The equation for the given wave is:

Vs = Vm*sin(4t + 30^o)

My question is how does the 4t change this graph? Also, What does the phase angle change*?

If the equation was just Vs = Vm*sin(4t), how would the graph change?

Thank you!

PS - Please excuse the terrible mspaint graph!
 

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Well, I may be very wrong, but the angle is the phase angle of the sinusoid. This comes into play when dealing with power factors. ie, phase matching.
hope this sheds some light...


(take everything with a grain of salt, it tastes better that way)
 
Maxwell said:
Lately, I have been trying to get a deeper understanding of a few concepts, and I was trying to analylize a wave I found in my textbook:

I know the sinusoidal equation is:

Vs = Vm*sin({\omega}t + {\phi})

The equation for the given wave is:

Vs = Vm*sin(4t + 30^o)

My question is how does the 4t change this graph? Also, What does the phase angle change*?

If the equation was just Vs = Vm*sin(4t), how would the graph change?

Thank you!

PS - Please excuse the terrible mspaint graph!
you need to understand the relationship between radians and degrees..
{\omega}=2{\pi}/t radians /sec
and how to convert between the two.. and where each one is on the graph ..
 
Maxwell said:
My question is how does the 4t change this graph? Also, What does the phase angle change?
If the equation was just Vs = Vm*sin(4t), how would the graph change?
Actually the graph you attached explains it all.
Phase is basically offset of the regular sin(x) or cos(x), i.e. shift along the horizontal axis. While angular velocity/frquency (w = 4t) is the frequency of the signal, i.e. if it were just t, the sinusoidal graph would have just one wave-length through the period of 2pi, for 4t crudely speaking, you have 4 wave-lengths crammed into segment of 2pi.
So, I would read-up on basic relationship of frequency/period and how f(x) behaves: f(cx), f(x + c) and so on, it's explained in Calculus I.
 
It maybe worth looking into this deeper to show how different variables act on the wave.

Take the formula Vs = A*sin({\omega}t + {\phi})+C

The A is the amplitude and represents the different between the upper and lower peaks.

The \omega is the angular velocity: \omega = 2{\pi}f = 2{\pi}/T

The \phi is the phase angle, i.e. the horizontal offset graphically speaking.

The C is the vertical offset from the x-axis, usually defined as the DC element of the waveform (in electronics).
 

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