jack1234
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Inequality question involving Ceiling
I have seen the following sentence in the reference book,
B-1 >= Ceiling(N/B) implies that B must at least be large enough to satisfy
B*(B-1) >= N
but how does
B-1 >= Ceiling(N/B)
implies
B*(B-1) >= N
?
Note that B and N are natural numbers.
I have seen the following sentence in the reference book,
B-1 >= Ceiling(N/B) implies that B must at least be large enough to satisfy
B*(B-1) >= N
but how does
B-1 >= Ceiling(N/B)
implies
B*(B-1) >= N
?
Note that B and N are natural numbers.
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