Logic - clarification needed about implication

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In logic, the implication P→Q is considered true when P is false, regardless of the truth value of Q. This is because the statement does not provide information about Q when P is not true, making it logically consistent. Similarly, when both P and Q are false, P→Q is still defined as true to maintain logical coherence across all truth combinations. The definitions ensure that logical implications function correctly, aligning with the principle that "if P is true, then Q must be true." Thus, the truth table for P→Q aligns with the contrapositive (not Q)→(not P), reinforcing the validity of these logical statements.
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If P→Q, and P is false but Q is true, then why is P→Q true? To me, it seems as though we shouldn't be able to do proceed because there isn't enough information. Same goes when P and Q are both false, how does that suggest P→Q is true?
 
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"If it rains, the street gets wet"
This statement is true, even if I spill water on the street (without rain).
More general: It cannot be false, if it does not rain. It just does not give any information about the street in that case.
 
Another reason for those definitions is so that logic "works" the way it should, for every combination of "true" and "false".

For example, "P implies Q" means the same (in ordinary English) as "if P is true, then Q is true", which means the same as "if Q is false, then P is false".

So the truth table for P→Q must be the same as for (not Q)→(not P),

That means P→Q must be defined as true, when P and Q are both false.

You can create a similar argument to show how P→Q must be defined with P is false and Q is true.
 
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