Rocket Burning fuel causing change in mass

AI Thread Summary
The discussion centers on calculating the final velocity of a rocket as it burns fuel at a constant rate. The initial scenario involves a 100 kg rocket with 50 kg of fuel, producing a thrust of 100 N. The challenge arises from the changing mass of the rocket as fuel is consumed, leading to questions about using average mass for calculations. It is clarified that since the acceleration is not constant, one cannot simply use average mass; instead, integration of a differential equation is necessary to accurately determine the final velocity. The conversation emphasizes the complexity of real-world rocket fuel consumption and the importance of applying the correct mathematical approach.
kaikalii
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I made up a scenario: Let's say I have a rocket at rest in space. The rocket initially weighs 100 kg, 50 kg of which is fuel. If the fuel burns at a constant rate of 1 kg/s and produces a thrust of 100 N out the back of the rocket, what will the rocket's velocity be after it runs out of fuel?

From F=ma and V=v0+at, I derived V=Ft/m. The force is 100 N, and it would take 50 s to burn 50 kg of fuel at 1 kg/s, so it would be V=100*50/m.

My question is: What would I use for the mass, since it is changing at the fuel burns? When I assumed that it was just the average mass, 75 kg, I got the final velocity ≈ 66.7 m/s. Am I supposed to just use the average mass since the fuel is burned at a constant rate? Does rocket fuel in the real world burn at a constant rate, or exponentially? If it was exponential, could I just use calculus to find the average mass and then plug it in?
 
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kaikalii said:
I made up a scenario: Let's say I have a rocket at rest in space. The rocket initially weighs 100 kg, 50 kg of which is fuel. If the fuel burns at a constant rate of 1 kg/s and produces a thrust of 100 N out the back of the rocket, what will the rocket's velocity be after it runs out of fuel?

From F=ma and V=v0+at, I derived V=Ft/m. The force is 100 N, and it would take 50 s to burn 50 kg of fuel at 1 kg/s, so it would be V=100*50/m.

My question is: What would I use for the mass, since it is changing at the fuel burns? When I assumed that it was just the average mass, 75 kg, I got the final velocity ≈ 66.7 m/s. Am I supposed to just use the average mass since the fuel is burned at a constant rate? Does rocket fuel in the real world burn at a constant rate, or exponentially? If it was exponential, could I just use calculus to find the average mass and then plug it in?

What you are asking about is known as the "Rocket Equation". Here is a tutorial from NASA:

http://exploration.grc.nasa.gov/education/rocket/rktpow.html

:smile:
 
kaikalii said:
My question is: What would I use for the mass

You need to use ## 50 + 50 ( 1 - \frac{t}{50} ) ##. Because the acceleration is not constant, you cannot use V=v0+at or work with an average mass though: you need to integrate a differential equation.
 
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