Solve the Puzzle: Find the Odd Coin in 3 Weighings

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To identify the odd coin among twelve coins using a balance in just three weighings, a strategic approach is required. The process involves dividing the coins into groups and comparing their weights to systematically eliminate possibilities. Initially, the coins can be split into three groups of four. By weighing two of the groups against each other, one can determine if the odd coin is in one of those groups or in the unweighed group. Subsequent weighings further narrow down the possibilities, allowing for the identification of the odd coin and whether it is heavier or lighter. This classic problem has variations that increase in complexity, such as those found in the "IBM Ponder This" challenges, which offer more difficult scenarios for enthusiasts.
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You have twelve coins, eleven identical and one different. You do not know whether the "odd" coin is lighter or heavier than the others. Someone gives you a balance and three chances to use it. The question is: How can you make just three weighings on the balance and find out not only which coin is the "odd" coin, but also whether it's heavier or lighter?
 
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this has been posted here repeatedly. There's a variation to this coin problem that is much more complex, I saw it at "ibm ponder this" a couple of years ago...it makes this problem seem too easy. You can search there "ponder this" database if you want a real challenge.
 
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