Math Rounding Help: Find the Nearest Thousandths and Tenth

  • Thread starter Thread starter Gamma
  • Start date Start date
AI Thread Summary
Rounding 38.90952 to the nearest thousandth results in 38.910, while rounding 320.945 to the nearest tenth gives 320.9. The initial rounding provided was incorrect for the thousandths place. The discussion confirms the correct rounding values and clarifies any confusion. Overall, the rounding principles for these numbers are accurately applied.
Gamma
Messages
355
Reaction score
11
Hello,

I need to ask this question although it is a baby question in math.:blushing:

Round 38.90952 to the nearest thousandths = 38.909
Round 320.945 to the nearest tenth = 320.9

Is the above correct.

Thanks,
 
Physics news on Phys.org
To the nearest thousandth 38.90952 is 38.910 and to the nearest tenth 320.945 is 320.9
 
To the nearest thousandth 38.90952 is 38.910 and to the nearest tenth 320.945 is 320.9


That makes sense. Sorry about my frozen brain.

Thanks,
 
I tried to combine those 2 formulas but it didn't work. I tried using another case where there are 2 red balls and 2 blue balls only so when combining the formula I got ##\frac{(4-1)!}{2!2!}=\frac{3}{2}## which does not make sense. Is there any formula to calculate cyclic permutation of identical objects or I have to do it by listing all the possibilities? Thanks
Since ##px^9+q## is the factor, then ##x^9=\frac{-q}{p}## will be one of the roots. Let ##f(x)=27x^{18}+bx^9+70##, then: $$27\left(\frac{-q}{p}\right)^2+b\left(\frac{-q}{p}\right)+70=0$$ $$b=27 \frac{q}{p}+70 \frac{p}{q}$$ $$b=\frac{27q^2+70p^2}{pq}$$ From this expression, it looks like there is no greatest value of ##b## because increasing the value of ##p## and ##q## will also increase the value of ##b##. How to find the greatest value of ##b##? Thanks
Back
Top