Find Solution for 4 sin(x) = 1.8 in 2nd Quadrant

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To solve the equation 4 sin(x) = 1.8 in the second quadrant, first simplify to sin(x) = 9/20. The initial solution is found using x = arcsin(9/20), which yields a value in the first quadrant. To find the corresponding angle in the second quadrant, apply the identity sin(π - x) = sin(x). The final solution in the second quadrant is x = π - arcsin(9/20).
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This problem seems really easy but I don't know how to solve it. Can someone please help me?

Give the solution in radians which is in the second quadrant for the equation
4 sin(x) = 1.8
 
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4\sin x =1.8

\sin x = \frac{9}{20}

x = \arcsin(\frac{9}{20})

That answer will give you the solution in the first quadrant.

Use the fact \sin (\pi - x) = \sin x to finish off.
 
Since ##px^9+q## is the factor, then ##x^9=\frac{-q}{p}## will be one of the roots. Let ##f(x)=27x^{18}+bx^9+70##, then: $$27\left(\frac{-q}{p}\right)^2+b\left(\frac{-q}{p}\right)+70=0$$ $$b=27 \frac{q}{p}+70 \frac{p}{q}$$ $$b=\frac{27q^2+70p^2}{pq}$$ From this expression, it looks like there is no greatest value of ##b## because increasing the value of ##p## and ##q## will also increase the value of ##b##. How to find the greatest value of ##b##? Thanks

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