Superposition of two waves and infinitely many waves?

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Wave packets are formed by superposing two or more waves of slightly different frequencies, resulting in periodic patterns if the number of waves is finite. Nonlinear Schrödinger equations typically describe non-periodic wave packets, which can exhibit a single peak. To create a single peak wave packet, a continuum of frequencies is necessary rather than discrete ones. Superposing an infinite range of frequencies, such as from 2Hz to 3Hz, can produce a single peak wave packet, with the width of the wave packet inversely related to the range of frequencies. This relationship illustrates the uncertainty principle, where increasing frequency range narrows the temporal width of the wave packet.
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Hi. I am struggling with wave packets.
I know wave packets are generated when two or more waves of slightly different frequencies are superposed together.
When considering only two or finite number of waves superposed together, the resulted wave shall be still periodic? I mean the "peak" of wave packet will actually repeat itself periodically, right? Just see the superposition of two sine waves of slightly different frequencies.

But are wave packets referred in nonlinear schrodinger equation correspond to "non-periodic" wave packets? I mean, the wave packet shall have just ONE single peak?

How do we produce that ONE single peak wave packet? Is it realistic in nature?
I am guessing that we will have ONE single peak wave packet as long as we have infinitely many waves superposed together (rather than finite number of waves). Is this the sufficient condition for having "one peak wave packet"?

Let's say I superpose waves of frequencies from 2Hz to 3Hz, there will be infinitely many waves. If the range of frequency is now 2Hz to 2.000001Hz, there will be still infinitely many waves, right? So, are they going to produce "one peak wave packet" anyway?

Please kindly help. THANKS.
 
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hanson said:
Hi. I am struggling with wave packets.
I know wave packets are generated when two or more waves of slightly different frequencies are superposed together.
When considering only two or finite number of waves superposed together, the resulted wave shall be still periodic? I mean the "peak" of wave packet will actually repeat itself periodically, right? Just see the superposition of two sine waves of slightly different frequencies.
Yes, if the number of frequency components is finite, then the resultant wave will still be periodic.
hanson said:
But are wave packets referred in nonlinear schrodinger equation correspond to "non-periodic" wave packets? I mean, the wave packet shall have just ONE single peak?
The term "Wave-packet" usually refers to non-periodic waveforms.
hanson said:
How do we produce that ONE single peak wave packet? Is it realistic in nature? I am guessing that we will have ONE single peak wave packet as long as we have infinitely many waves superposed together (rather than finite number of waves). Is this the sufficient condition for having "one peak wave packet"?
A single peak is produced by using a continuum of frequencies rather than a series of discrete frequencies
hanson said:
Let's say I superpose waves of frequencies from 2Hz to 3Hz, there will be infinitely many waves. If the range of frequency is now 2Hz to 2.000001Hz, there will be still infinitely many waves, right? So, are they going to produce "one peak wave packet" anyway?
Yes, this is correct. The effect of increasing the range of frequencies is to reduce the temporal width of the wave-packet. It is a manifestation of the uncertainty principle because the spectral and temporal widths are inversely dependent on one another, and their product can never go below a certain amount.
hanson said:
Please kindly help. THANKS.
You're welcome.

Claude.
 
The (nonlinear) Gaussian (one packet) wavefunction is given by the equation:

S(x,t)/A=exp(-(x-x0)2/4a2) exp(ip0x/h) exp(-iw0t)

Where S is Psi, h is Planck's constant divided by 2(pi), and w is omega
 

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