- #1
odie5533
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Homework Statement
The following is the data I collected. I set a weight on a spring and measured how far the spring was stretched. The spring was not oscillating, just stretched and left at rest.
Load (kg):
0.300
0.400
0.500
0.600
0.700
0.800
0.900
Weight (Converted the above load into N):
2.94
3.92
4.90
5.88
6.86
7.85
8.83
5.39
6.37
Stretch (m):
0.059
0.076
0.095
0.115
0.134
0.154
0.174
0.105
0.125
The question is, how do I find the work from the above and how do I find the elastic potential energy.
Homework Equations
(1/2)kx^2
The Attempt at a Solution
[tex]Work = Fd[/tex]
[tex]W = (2.94)(0.059) = 0.17346[/tex]
[tex]F = kx[/tex]
[tex]k = F/x[/tex]
[tex]2.94 / 0.059 = 49.8[/tex]
[tex]U_{elastic} = \frac{1}{2}kx^2[/tex]
[tex]U_{elastic} = \frac{1}{2}(49.8)(0.059^2) = 0.08673[/tex]
I'm pretty sure I did something wrong. It also asks me to compare the work done and the elastic potential energy. I thought W = Ue in this case, but the calculations show differently. But I think the calculations are wrong. Any help would be greatly appreciated.