What is the significance of strong equivalence in topological space metrics?

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The discussion focuses on the significance of strong equivalence in metrics defined on the product space X×Y, specifically using the metric dp. It explains that as p approaches infinity, the metric converges to the maximum of the individual metrics dX and dY. The concept of strong equivalence is clarified, stating that two metrics are strongly equivalent if they can be bounded by positive constants, ensuring they generate the same topology. The example of setting X=Y=R illustrates how different values of p yield familiar metrics like the taxicab and Euclidean metrics. Overall, understanding these metrics and their relationships enhances comprehension of topological properties in metric spaces.
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A metric dp on the topological space X×Y, with dX(x,y) and dY(x1,y1) being metrics on X and Y respectively, is defined as

dp((x,y),(x1,y1))=((dX(x,y))p+(dY(x1,y1))p)1/p

What does each dp((x,y),(x1,y1)) mean (geometrically or visually)?

as p\rightarrow\infty,

d\infty=max((dX(x,y),dY(x1,y1)).

What is the meaning of "max(A,B)"?

Each of the dp((x,y),(x1,y1)) are strongly equivalent; what does this mean geometically?
 
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You probably want p>=1 for d_p to actually be a metric. Anyway, have you tried putting X=Y=R? This should be revealing, e.g. if p=1 you get the "taxicab metric" and if p=2 you get the usual Euclidean metric. For other p>1, you may want to sketch the unit balls of (R^2, d_p) to get a feel for what the metric d_p does.

max(A,B) means what you would expect it to be; namely, max(A,B) is A if A>=B and B otherwise.

Finally, two metrics d and d* on a metric space Z are said to be strongly equivalent if you can find positive constants M and m such that the string of inequalities
m d(x,y) < d*(x,y) < M d(x,y)
holds for all x and y in Z. This essentially means that inside each d-ball you can find a d*-ball and vice versa. In particular, this implies that the metrics d and d* generate the same topology on Z.
 
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Thanks. I've been worrying about what they were fr a while. It seems kinda obvious now.

Thanks again!
 
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