fisico30 said:
I am independently studying the topic on the book by Saleh.
Great book. I do not know your exact level of understanding, but i will try to answer your questions as basic as possible.
fisico30 said:
a) i still do not get what this uncertainties are
b)they are defined as the uncertainties of the phasor components. But a phasor is just a mathematical too. What is real about these uncertainties. Is it because together, these two determine (only together) the amplitude and phase of the field?
There are several uncertainies, which can be applied to em-fields. The easiest one to understand is the uncertainty in terms of the field amplitude and phase. So the field amplitude uncertainty leads to uncertainty in the photon number and the phase uncertainty has some influence on the coherence properties of the light field. Honestly, I really can't explain this any better than just to say, that the amplitude and phase of an em-field do not have precise values, but a certain spread.
fisico30 said:
Why would the "registration of the photons be statistically independent".
Let's start with the classical point of view. Imagine some light field with constant intensity. Now you split the light beam and direct it towards two photodetectors, which take "single pictures" simultaneously. On every detector you will now see the same average number of counts. For simplicity assume a low count number of 1 detection every 10 pictures on a single photodetector. Now, you want to know, how often there will be a detection of a photon on both detectors simultaneously. In the case of statistical independence the probability of a joint detection will just be the product of the single detection probabilities. So you will expect 1 out of 100 pictures to show a joint detection (1 out of 10 on one detector times 1 out of 10 on the second detector). This is what one would expect to see from a classical point of view and this is, what one indeed sees, when coherent light is examined.
fisico30 said:
Also, your words"at the destruction of a photon should leave the state unchanged, which is not possible with a state of precisely defined photon number". Why can u elaborate on that, in simple terms?
Ok, there are several possibilities to interpret the result with the two photodetectors, I mentioned beforehand. The fact, that the detection of one photon does not change the possibility to detect another photon afterwards might seem trivial at first, but it isn't. The case I mentioned means, that the photon number fluctuations on both detectors are completely random and not correlated to each other.
Now consider the same setup, but a different light source: a single atom. A single atom will also produce a light field with constant average intensity, but it will only emit one photon at a time. So imagine you have again count rates of 1 detection every 10 pictures on both detectors. Taking into account, that the single atom can only emit one photon per cycle, you will now find, that there will be no joint detections at all. One photon can't be detected at both detectors simultaneously. So in this case the detection (and therefore destruction) of a photon changed the light field and the photon detections on both detectors are not statistically independent anymore. One could say, that the photon number fluctuations at both detectors are anticorrelated.
Now imagine an em-field with strongly fluctuating amplitude, but constant average intensity on a timescale, which is longer than the timescale of the fluctuations. Let me assume 1 count in 10 pictures per detector again. As the intensity/photon number is proportional to the square of the amplitude, you will again find, that the photon detections are not statistically independent, but you will have more joint detection than expected, because in the moments of high amplitude fluctuations, the photon number will be far above average and in the moments of low amplitude fluctuations, it will be far below. So in this case, the photon number fluctuations on both detectors will be correlated. Either the photon number is above average at both detectors simultaneously or it is below average at both detectors simultaneously. This is, what you would expect for thermal light like sunlight, the emission of a lightbulb and so on.
So the classical hypothesis, that the measurement of the intensity/photon number at one moment does not change the photon detection probability for later moments is not always true. However the situations, in which this classical hypothesis is right, can not have a definite photon number. Imagine a state with exactly 5 photons. Now one is detected and thereby destroyed. It is obvious, that the probability for detecting a photon for a state with 4 photons will be different from the probability for detecting a photon for a state with 5 photons. So to cancel this effect, the photon number noise needs to be on the order of the average photon number, which is a feature of the Poisson distribution.