Schrodinger Equation for a central 2D potential

EliotHijano
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Hello,
I would like to ask something about central potentials. When I am working in 3D, I haven´t got any problem solving the schrodinger equation since I use the following change of variables:
-\frac{\hbar^{2}}{2m}\nabla^{2}\Psi+V(r)\Psi=E\Psi
\Psi=\frac{\chi}{r}
With this change of variables, I can solve and understand the equation, but when I am working in 2D( usig r and \varphi) I can't solve the equation because the laplacian is different. The concrete potential distribution I want to study is the following:
V(\vec{r})=0 \stackrel{if}{\rightarrow} r<a
V(\vec{r})=\infty \stackrel{if}{\rightarrow} r>a
And I would like to solve the equation for the first and the second energy levels of the system. I would appreciate some tips, thank you.
 
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It's not as easy as 3D. The bound states are Bessel functions:
\psi=J_m(kr)\cos(m\theta), with the energy determined by
J_m(ka)=0.
 
Thank you very much clem, that will be really useful for me.
 
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