How can gradient be zero if its a normal vector?

AI Thread Summary
The discussion centers on the concept of the gradient as a normal vector to equipotential surfaces defined by the equation φ(x,y,z) = 0. It raises the question of how the gradient can be zero for certain surfaces, as this would imply the absence of a normal vector, which seems contradictory. The conversation highlights that while the gradient is typically non-zero for most surfaces, there are instances where grad φ equals zero, particularly in constant potential fields. This leads to the inquiry about the uniqueness of equipotential surfaces when φ is constant, such as φ(x,y,z) = 2. The exploration reveals complexities in understanding gradients and normal vectors in various contexts.
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Physical interpretation of gradient says that its a vector normal to equipotential (or level) surface \phi(x,y,z) = 0
but what about other surfaces, say the surface which are not equipotential?
This is my first question.

ok, now
as grad \phi is a vector normal to surface it can't be 0. Because that would mean that surface have no normal vector, or say a normal vector of indeterminate direction (as 0 vector is of indeterminate direction). how can it be possible that a surface has no normal vector, more specifically a 0 vector as its normal vector?
But I have seen many examples in which grad \phi is 0.
So doesn't that contradicts the assumption that grad \phi is a normal vector?
 
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Equipotential surfaces are defined by the eqution:
\phi(x,y,z) = C (C is constant)
But consider the contant potential field ,say \phi(x,y,z) = 2,can you find a unique equipotential surface for it?
 
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