What is the correct answer for 3r - 3p + 5q if p = 4, q = -2, r = 3, and s = -5?

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To evaluate the expression 3r - 3p + 5q with the values p = 4, q = -2, and r = 3, the calculation proceeds as follows: 3(3) - 3(4) + 5(-2) results in 9 - 12 - 10. The correct answer is -13, confirming the math book's solution. The initial miscalculation of -7 arose from incorrect arithmetic in combining the terms. The final evaluation clearly shows that the accurate answer is indeed -13.
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p = 4
q = -2
r = 3
s = -5

on that basis, evaluate this expression:

3r - 3p + 5q

I make it to be -7 (15 - 12 + (-10)
But my math book says the answer is -13. Can anyone explain where I have gone wrong?
Thanks
 
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3r - 3p + 5q

= 3(3) - 3(4) + 5(-2)

= 9 - 12 -10

= -13
 
Thanks!
 
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Since ##px^9+q## is the factor, then ##x^9=\frac{-q}{p}## will be one of the roots. Let ##f(x)=27x^{18}+bx^9+70##, then: $$27\left(\frac{-q}{p}\right)^2+b\left(\frac{-q}{p}\right)+70=0$$ $$b=27 \frac{q}{p}+70 \frac{p}{q}$$ $$b=\frac{27q^2+70p^2}{pq}$$ From this expression, it looks like there is no greatest value of ##b## because increasing the value of ##p## and ##q## will also increase the value of ##b##. How to find the greatest value of ##b##? Thanks
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