Can the number of edges determine isomorphism in graphs?

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The discussion centers on whether having the same number of edges is sufficient to prove that a graph G and its complement G' are isomorphic. It is clarified that this is not enough, as demonstrated by examples of graphs with four vertices and three edges that do not have isomorphic complements. To establish isomorphism, one must define a function that maps vertices of G to G' while preserving edge connections. The initial inquiry reflects a common misconception about graph isomorphism. Understanding the requirements for proving isomorphism is crucial in graph theory.
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Hi all,

If I have to prove that the graph G and its complement G' are isomorphic, then is it enough to prove that both G and G' will have the same number of edges. Intuitively its clear to me, but how do I prove this. If there's a counterexample, please post.

Thanks in advance.
 
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AlbertEinstein said:
Hi all,

If I have to prove that the graph G and its complement G' are isomorphic, then is it enough to prove that both G and G' will have the same number of edges. Intuitively its clear to me, but how do I prove this. If there's a counterexample, please post.

Thanks in advance.

That is certainly not enough. Consider the graphs of four vertices and three edges. They are not isomorphic to each of their complements.
To prove an isomorphism you will need to define a function f : G --> G' such that an edge between v_1 and v_2 implies that there is an edge between f(v_1) and f(v_2).
 
Oh yeah, I got the point.

Thanks for the help.
 
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