Line of intersection of two planes

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The cross product of the normal vectors of two planes provides the direction vector for their line of intersection. This is because the line of intersection lies within both planes, and the normal vector is perpendicular to any line in the plane. Thus, the cross product results in a vector that is perpendicular to both normals, indicating it is parallel to the line of intersection. It's important to note that the cross product itself is a vector with direction but no specific position in space. Understanding this relationship clarifies the geometric properties of the intersection of planes.
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Hi,
I am having difficutly figuring out why the cross product of the normal vectors of each plane gives the direction vector of the line of intersection. Anyone care to try to explain?


Thanks!
 
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The line of intersection lies in both planes. The normal to a plane is (by definition) perpendicular to any line in the plane. The cross product then gives you a line perpendicular to both normals, so that it must be parallel to the line of intersection.
 
mathman said:
The line of intersection lies in both planes. The normal to a plane is (by definition) perpendicular to any line in the plane. The cross product then gives you a line perpendicular to both normals,
therefore lieing in both planes, therefore along the line of intersection
so that it must be parallel to the line of intersection.
 
therefore lieing in both planes, therefore along the line of intersection

The cross product is a vector, NOT a line is space - that is, it has a direction but no position. Therefore it doesn't lie anywhere, but it is parallel to the line of intersection.
 
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