Emf induced in a ring rolling in non-uniform magnetic field

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When a ring rolls in a non-uniform magnetic field, an increasing flux linkage suggests that EMF should be induced. However, connecting two points on the ring, such as the instantaneous axis of rotation and a diametrically opposite point, raises a contradiction since it seems to imply that induced EMFs would cancel out. The discussion clarifies that the EMFs may not be equal in magnitude due to the varying magnetic field experienced by free electrons on opposite sides of the ring. This variation in the Lorentz force acting on the electrons leads to differing induced EMFs. The complexity of the situation highlights the nuances of electromagnetic induction in non-uniform fields.
Jishnu Dey
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I have got a doubt regarding the situation when a ring rolls in a non-uniform magnetic field. We can see that the flux linkage is increasing (considering dB/dt to be positive). So EMF should be induced in the loop.
But if we join any two points, say the instantaneous axis of rotation and the diametrically opposite point, we will get two rods completing a loop with EMFs being induced in opposite direction and equal in magnitude, which should cancel out (I am not talking about the potential difference between these points, I am just talking about the EMF of the loop).

This contradiction is confusing me. Please help.
 
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Jishnu Dey said:
But if we join any two points, say the instantaneous axis of rotation and the diametrically opposite point, we will get two rods completing a loop with EMFs being induced in opposite direction and equal in magnitude
Are you sure they are equal in magnitude? Why should they be?
 
If the ring is spinning in a non-uniform B field. The free electrons in the ring would each experience a different Lorentz force at opposite sides of the ring because B would be different.
 
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