Number of unique paths in Pascal's Triangle

AI Thread Summary
The discussion centers on proving that the number of unique paths from the entry {0,0} to {n,i} in Pascal's Triangle equals pascal(n,i) using induction. The base case for n=1 is straightforward, as there is only one path to each element in the row. Participants note that each value at {n,i} can be expressed as nCi, which relates to combinations. The main challenge is determining how to reach the ith element in the nth row while adhering to movement restrictions. Insight is sought on how to approach the proof by considering the elements that lead to {n,i}.
tarmon.gaidon
Messages
30
Reaction score
0

Homework Statement


Let pascal(n,i) be the value of the ith element of the nth row of Pascal's triangle. Using induction show that the number of unique paths from entry {0,0} to entry {n,i} in Pascal's triangle is equal to pascal(n,i).

The Attempt at a Solution


The base case n=1 seems easy enough to prove. It is obvious that there is only one path to each of the two elements in the nth row.

It was brought to my attention that each value at {n,i} in Pascal's triangle can be represented by nCi.

That being said I am not sure how to precede. I am just looking for some insight on how to continue.

Any suggestions would be greatly appreciated.
 
Physics news on Phys.org
Hint: How (from which elements) can you reach the ith element in the nth row, if movement is restricted in the appropriate way?
 
Back
Top