Equipartition Thm: mv_x^2/2 = k_B T/2

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< \frac{mv_{x}^{2}}{2}> \equiv s\int_{-\infty }^{\infty} \frac{mv_{x}^{2}}{2} \rho (v_{x}) dv_{x}=\frac{k_{B}T}{2}

im stuck
 
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Plug in the expression for ρ(vx) inside the integral and then actually calculate the integral, or look it up in a table of integrals.
 
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