Find the inverse Laplace transform?

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The discussion revolves around finding the inverse Laplace transform of the function e^(-3pi*s)/(s^2+2s+3). Participants emphasize the need to factor out e^(-3pi*s) to simplify the expression to 1/((s+1)^2 + 2). The confusion arises regarding the steps to derive the final answer, which is given as y=(1/sqrt(2))u3pie^(-(t-3pi))*sin(sqrt(2))(t-3pi). There is a reminder about the forum rules against posting continuations as new threads to maintain discussion continuity. The thread highlights the importance of showing work in problem-solving.
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Homework Statement


Find the inverse Laplace transform of e^(-3pi*s)/(s^2+2s+3).


Homework Equations


I know that you're supposed to factor out the e^(-3pi*s) and the other part becomes 1/(s+1)^2+2 but how do you get the answer? I'm confused.


The Attempt at a Solution


The answer is y=(1/sqrt(2))u3pie^(-(t-3pi))*sin(sqrt(2))(t-3pi)
 
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Success said:

Homework Statement


Find the inverse Laplace transform of e^(-3pi*s)/(s^2+2s+3).


Homework Equations


I know that you're supposed to factor out the e^(-3pi*s) and the other part becomes 1/(s+1)^2+2 but how do you get the answer? I'm confused.


The Attempt at a Solution


The answer is y=(1/sqrt(2))u3pie^(-(t-3pi))*sin(sqrt(2))(t-3pi)

Show your work. According to PF Rules you are not supposed to just ask us to do the problem for you.
 
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I already did some work in #2 template. I really don't know what to do next.
 
Question: A clock's minute hand has length 4 and its hour hand has length 3. What is the distance between the tips at the moment when it is increasing most rapidly?(Putnam Exam Question) Answer: Making assumption that both the hands moves at constant angular velocities, the answer is ## \sqrt{7} .## But don't you think this assumption is somewhat doubtful and wrong?

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