Understanding Time Elasticity: How to Visualize the Concept

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What do we mean by "Time is elastic"?

How can we see that time is elastic? Is there anyway to illustrate this?
 
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I never heard anyone say that before - I don't know what it is supposed to mean, if anything.
 
Well, all I have heard that spacetime is elastic which curves as a large mass is put on it just like elastic and creates gravitational force. I think because time warps, it is supposed to be elastic.
 
Caesar_Rahil said:
Well, all I have heard that spacetime is elastic which curves as a large mass is put on it just like elastic and creates gravitational force. I think because time warps, it is supposed to be elastic.

Space-time does curve in the presence of large masses. I don't think it's good to take the elastic sheet analogy too seriously, though, so I wouldn't say that space-time is "elastic", I'd just say that it deforms in the presence of large masses.
 
gunblaze said:
What do we mean by "Time is elastic"?

I don't think that time is experessed scientifically as elastic...Probably someone wnated to make it easier to udnerstand, it's the 1st time to read such an expression..Except when i was trying to explain Einstein's marvels to some kids..
 
I thought about this question for a long period of time. why time is elastic? I thought that if time is elastic ,so it must be able to deform. My imagination told me that deformation of time is represented by time dilation. If time can dilate (deform) ,so it must be elastic. In case you asked yourself about its high elasticity. I asked myself the same question and I think that I have reached a convincing answer. As time can dilate until it almost reach infinity (it doesn’t reach infinity) therefore, it must be of high elasticity. If I am wrong just tell me. I am not sure about what I am saying. It is just my imagination.
 
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From $$0 = \delta(g^{\alpha\mu}g_{\mu\nu}) = g^{\alpha\mu} \delta g_{\mu\nu} + g_{\mu\nu} \delta g^{\alpha\mu}$$ we have $$g^{\alpha\mu} \delta g_{\mu\nu} = -g_{\mu\nu} \delta g^{\alpha\mu} \,\, . $$ Multiply both sides by ##g_{\alpha\beta}## to get $$\delta g_{\beta\nu} = -g_{\alpha\beta} g_{\mu\nu} \delta g^{\alpha\mu} \qquad(*)$$ (This is Dirac's eq. (26.9) in "GTR".) On the other hand, the variation ##\delta g^{\alpha\mu} = \bar{g}^{\alpha\mu} - g^{\alpha\mu}## should be a tensor...
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