Developping sin(x) on [0, pi] as a serie of cosines

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Developing sin(x) as a series of cosines on the interval [0, pi] while requiring a period of 2pi raises questions about the feasibility of the approach. The discussion highlights the attempt to extend sin(x) to an even function by defining it as -sin(x) for x < 0. However, this results in a cosine series that only maintains a period of pi, contradicting the requirement for a 2pi period. The conclusion suggests that while the initial assumption seems plausible, the resulting function's period does not align with the desired conditions. Thus, the task is deemed impossible under the specified constraints.
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Am I crazy or this is impossible to do if we require that the period of the extended even function be 2pi ?

Yet, this question comes in my textbook before the section concerning Fourier extension of functions of period other than 2pi. So there must be a way?
 
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I'm pretty sure it's possible. Extend sin(x) before x=0 as -sin(x) so the function is even. Now do a cosine series on the interval [-pi,pi] and it will be valid on [0,pi] and have period 2pi.
 
This is what I did, but the period of this function (|sin(x)|) is pi.
 
Arr, you're right.
 
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