Tension Definition and 1000 Threads

[The problem involves the use of Lagrange's equations for conservative systems. I am first trying to solve it using Newton's mechanics, similar to that of a school student] Diagram : The diagram of the problem is shown to the right. Solution : The tension is the same all over the (same) rope -...

I can't understand what is going on here. My intuition tells me that the traction pulling on the block should be equal to F. Apparently, however, the problem would have me believe that this is not the case, as it gives me a 30° angle at which the force acts and a 6-8-10 triangle as ways to...

Hello, I have tried to resolve this using the fact that we consider the weight to be normal, so I resolved the tensions in both the strings using an angle of 45 degrees. Upon solving these simultaneously T2*cos(45) + T1*cos(45) - 10 = 0 , T2*sin(45) - T1*sin(45) = 0, I have gotten T1 = 5√2 and...

Where D is sag, H is horizontal tension –w is cable weight per unit length –h is elevation difference between supports –S is span (horizontal difference between supports) This is the image of the problem: My main question is a conceptual one, is the pulling force I'm looking for simply the...

What does the scale read? At first I thought it might be zero as the two weights would cancel out. However, when thinking a bit further I wonder what the scale really reads. Is it the tension?

Let's say the center of mass of the ring (wheel) moved a distance ##x##, tension in the thread connecting wheel and ##A## be ##T## and tension in the thread connecting ##A,B## be ##T'## : Due to no slip condition , ##a=R\alpha## where ##R## is the assumed radius of wheel Since ##P## is IAOR ...

Since the pipe is light , net force and net torque acting on the pipe should be zero . Initially , ##T_A+T_B=3mg## by balancing torques about each end of the rod , we get : $$T_A=\frac{4mg}{3}$$ Let the tension in ##A## just after cutting ##B## be : ##T_A'## Let the normal reactions acting on...

After applying a small displacement along the axis between the center of the bottom ball and the projected center of the fourth ball, I got 4 as the answer, which is twice the correct value. I’m assuming I didn’t account for the fact that the tension force acts on both sides, so I ended up...

I really cant wrap my head around how I can find the tension i in the rope going from A to D via the smooth pulley B. P=4.91N Distances are in mm I assume I cant use the triangle EBD as it can be dynamic without the triangle ABC changing. I know I can find the y component of the tension in...

I'm struggling to get to the correct answer, which I posted down bellow. The pulleys are ideal, so I figured that m₁ and m₂ will both move upwards (towards the ceiling?) with the acceleration a, while m₃ will move downwards with the acceleration -a. Let T be the tension in the string which...

We know that net work done is equal to the change in kinetic energy, so we write: $$\Delta K = W$$ The tension is acting at angle ##\theta## due to the x axis, so we will only be taking its x component ##T_x = T \cos{\theta}##. Since we can look at this as one dimensional motion (##T_y## does no...

TL;DR Summary: Ping-pong ball hanging static from infinite plane of charge and a string Really struggling with this question. I'm not sure if I have set up the free body diagram correctly and don't know how to set up the x and y components

In classical mechanics, the potential energy stored in an elastic stretched string is the work done by the tension during the stretching process. Is this concept and formula the same in Special Relativity? Thanks in advance.

Hi everyone . I need help on the following problem. I built a current sensor that is based on the same principle as the Rogowski coil. Don't propose other alternative methods to measure the current because its application will be different and I don't want to talk about this. in reality what I...

The first question statement was under the chapter ##Newton's Laws Of Motion (Without Friction)##. Whereas, the second question was under ##Friction##. The free body diagram for the first question is given as: And the free body diagram for the other question is given as: In the first...

For point one I analyzed all of the forces, called the tension on the right ##T_2## and the left one ##T_1##, and taking as positive the clock-wise and upwards directions I found: $$\begin{cases} T_2 - mg = ma \\ N_2= T_2 + M_2g + T_1 \\ N_1= M_1g - T_1 \\ τ_{T_2} - τ_{T_1} = I_2 α_2\\ τ_{T1} =...

A cylindrical bag is made from a freely deformable fabric, impermeable for air, which has surface mass density σ; its perimeter L is much less than its length ##l##. If this bag is filled with air, it resembles a sausage. The bag is laid on a horizontal smooth floor (coefficient of friction µ =...

A few years back there was an issue called the Hubble tension where the observations were nor matching up to predictions when looking at the Early and late time data. I had heard that one possible explanation is due to our being in an underdense region but have also read a counter paper to...

I understand that in the initial condition both the net torque and net force are zero since the system is in a static state , the net torque remains zero as the mass down is being pulled , the two blocks get pulled towards the axis of rotation by a radial force but I am wondering what is...

for 4kg box: Fx = T m1a=T (4) (2.50) = T 10 = T for 6 kg box: Fx = Fa - T m2a = m2a - T 15 = 15 - T 15-15 = T 0 = T I assumed the tension would be the same for both boxes, they are supposed to be, so what did I do wrong and is the answer 10 or zero?

My interest is on part (a), the steps are clear. I thought the final solution ought to be ##T- 500 =50 ×0.2## ##T=500+10 = 510N## Unless I am missing something here, same query on part (b).

Pretty much what the title says. Everything that I can find online addresses the pendulum problem with the assumption that the rope is under tension to start. What if the rope is slack to start? Will there be an increase in force applied to the pivot point, say if a mass is dropped off a...

I'm the technical director for a theatre group and am looking at the best way to get an actor to use a rope to swing on stage. As we rent the theatre we use I need to run everything by their staff, who doesn't have a solid grasp of mechanics and physics. I proposed that we lower a pipe from...

I have been taught that speed of pulse is v = √(T/μ), but here tension varies at each point therefore I cannot just simply apply the formula. I think integration would be needed, I tried but ended up nowhere. Can someone help me find the time?

Here's the picture of the situation described, provided by the question. Here's a screenshot of the work I have done. Here's a screenshot of the submission screen. The issue is that I have one attempt left and am not sure what I am doing wrong. Based on the hints, I feel like I'm...

I calculated the acceleration which is 0.804m/s^2. From there I calculated the centripetal force which is 0.402N. I think my lack of answer is due to my lack of understanding of the concept of what the centripetal force is at the top of the circle. Would it not be Fc = Fg - Ft as the ball...

I have attached a screenshot of my rough work. First of all, is my interpretation of the question correct? Please see the diagram in purple. To me, this makes sense because a=v^2/r is the only equation from my coursework that seems to relates radius (which you can find from the length of the...

aaaah just realized the solution after typing here... ... at constant speed, ##a=0##, therefore ##T-mg = 0## ##T=(1050 × 10) =10, 500## Newtons or any insight...welcome. Maybe i should ask...when the lift is moving downwards and there is deceleration then would the Tension be treated in...

(a) x = 16.7 Since x > 4.88, k = k_2 = 111 N/m. T = F(16.7) = k_2*x = 111*16.7 = 1853.7 N The answer key says the correct tension is 2320 N. Any help is appreciated, I'm not seeing where my math is wrong.

Did I draw the free body diagram incorrectly by treating the two blocks as one system? My textbook claims the answer is 25 N.

My question is how come the tension in pulley 2 is pointing downwards. I was under the impression that tension always points away from the mass.

A rope wraps an angle θ around a pole. You grab one end and pull with a tension T0. The other end is attached to a large object, say, a boat. If the coefficient of static friction between the rope and the pole is µ, what is the largest force the rope can exert on the boat, if the rope is not to...

Body M has a mass of 80kg and monkey has a mass of 20kg. No friction between table and the object M. Can someone please explain to me if the acceleration of the system will be greater with monkey accelerating up or down(relative to the rope), and why. Monkey accelerates both up and down at...

I am working on a project that would help guide aspiring drummers and percussionists in determining what thickness of drumhead to select for the tuning they want and/or the “feel” they want. (More on just what “feel” is later). I’m trying to slowly work my way toward this starting with the...

Let the left string be T1 and the right string be T2. Pretend that the masses are NOT equal and that the total mass on the left is 3mg and the total mass on the right is 2mg. My first thought: Net torque = 3mgR1-2mgR1 Actual solution: Net torque = (T1-T2)*R Once again, the force that's used...

(a) The length ##h = L## for which the tension is minimum is the length that corresponds to the geostationary orbit, where the angular velocity of the cable matches the angular velocity of the Earth. This is because at this point, the centrifugal force balances the gravitational force, and the...

15 - Tension = 1.53*a T = 15 - 1.53*R*α T*0.33 - 1.10 = Iα Is this approach correct?

The thing with this exercise is that I don't think that the question makes sense at all (or, at least, is incomplete). First of all, we don't know if the mass moves with any of those tensions, therefore I cannot know which coefficient apply. Second of all, even if we suppose that the mass is...

Hi, If i have a system that consists of 2 pullies and 3 masses, what is the tension on each part of the string? I know that for 2 masses hanging on either side of a pulley, the tension is the same. But for 3 masses, and 2 ideal pullies(no friction) and inextensible string, is tension the same...

I found the tension of cable B by doing mg + Csin(37.1). I found C by doing 757(Tension in cable A) = Ccos(37.1). I was just wondering if the tension in cable D is equivalent to the tension in cable B. If possible please show the steps on how you determined if they are equivalent or not. Thank you!

For a better understanding of this exercise here is the image illustrating the scenario described in the statement: So to solve this exercise I began by drawing a forces diagram: I believe I have explained everything in the "Relevant equations" section. What am I doing wrong? The book that...

Hi all, To find out the tension. First I have to find out the a. 1. step F = ma F = (m1+m2) *a F = (1+3)*a F = 4*a F/4 = a F = 10N + 50 N F = 60 N 60/4 = 15 m/s^2 2.step T =( m1/ (m1 + m2)) * F T = (1/ 1+3) * 60 T = 15 N But the final result is 20N. Thanks for your help!

Hi. I need to tie some nylon monofilament fishing line so that it’s under tension. (Only moderate tension is needed – pulling by hand to make the line taut is sufficient.) I can tie one end to a support, e.g. using a using a ‘uni-knot’. Then the line will need to be stretched and the other end...

On question B, I've attempted a solution that I have posted. However, I don't think it's correct. Am I allowed to treat this rope that wraps around the rod as a "negative" force and simply attach it to the other side of the equation such that ## m_1g=m_2g+\mu_sN##?

This is the problem and my answer below it. my friends said it's 250 N and I say it's 100 N based on what I solved what am I missing ?? my try:

My Work so far: So there is a Force F applied to the right and since we have a no slipping condition we have a static friction force fs to the left. So the only thing that can move the center of mass (cm) of the yoyo is rotation. F would lead to a ccw rotation and fs to a clockwise rotation...

Is this even solvable? I don't know where to begin.

I have tried finding the tension of the string through the equation Net Force = T - mg = ma but I am struggling with coming up with the correct acceleration. Is my net force equation correct?