(1.73 x 10^3) (2.0 x 10^3) = 3.5 x_______?

  • Thread starter Thread starter land_of_ice
  • Start date Start date
AI Thread Summary
To calculate (1.73 x 10^3) (2.0 x 10^3) using a scientific calculator, first input 1.73, then press the "Exp" button followed by 3. Next, input 2.0, press "Exp" again, and then 3 to complete the multiplication. The result should yield a product expressed in scientific notation, specifically 3.46 x 10^6. The key is ensuring the correct sequence of inputs for the calculator to function properly.
land_of_ice
Messages
136
Reaction score
0

Homework Statement



Using this scientific calculator on line, how do you calculate (1.73 x 10^3) (2.0 x 10^3) = 3.5 x_______?
http://www.calculator.com/calcs/calc_sci.html

Homework Equations



(1.73 x 10^3) (2.0 x 10^3) = 3.5 x_______ <--------fill in the blank
When do you press the exp button and what other buttons do you push?

The Attempt at a Solution



So far pressing the exp button after pressing 3 did not work, some random number came up. The solution is in the manual for class work , but the steps on how to do it are not.
 
Last edited by a moderator:
Physics news on Phys.org
Press
1
.
7
3
Exp
3
 
Try this:
(1 x 10^3) x (1 x 10^3) = ?
= (10^3) x (10^3) = ?
= 1000 x 1000 = ?
 
I picked up this problem from the Schaum's series book titled "College Mathematics" by Ayres/Schmidt. It is a solved problem in the book. But what surprised me was that the solution to this problem was given in one line without any explanation. I could, therefore, not understand how the given one-line solution was reached. The one-line solution in the book says: The equation is ##x \cos{\omega} +y \sin{\omega} - 5 = 0##, ##\omega## being the parameter. From my side, the only thing I could...
Essentially I just have this problem that I'm stuck on, on a sheet about complex numbers: Show that, for ##|r|<1,## $$1+r\cos(x)+r^2\cos(2x)+r^3\cos(3x)...=\frac{1-r\cos(x)}{1-2r\cos(x)+r^2}$$ My first thought was to express it as a geometric series, where the real part of the sum of the series would be the series you see above: $$1+re^{ix}+r^2e^{2ix}+r^3e^{3ix}...$$ The sum of this series is just: $$\frac{(re^{ix})^n-1}{re^{ix} - 1}$$ I'm having some trouble trying to figure out what to...

Similar threads

Back
Top