16.1.9 Line Integral over space curves

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SUMMARY

The discussion focuses on evaluating the line integral $\displaystyle \int_C(x+y)ds$ over a straight-line segment defined by the parametric equations $x=t$, $y=(1-t)$, and $z=0$, transitioning from the point (0,1,0) to (1,0,0). The key method involves using the differential arc length $ds = \sqrt{(dx/dt)^2+(dy/dt)^2+(dz/dt)^2}dt$ to compute the integral. Participants emphasize the importance of correctly determining the limits for the parameter $t$ during the evaluation process.

PREREQUISITES
  • Understanding of line integrals in vector calculus
  • Familiarity with parametric equations
  • Knowledge of differential arc length calculations
  • Basic proficiency in calculus, particularly integration techniques
NEXT STEPS
  • Study the properties of line integrals in vector fields
  • Learn about parameterization of curves in three-dimensional space
  • Explore the application of the Fundamental Theorem of Line Integrals
  • Investigate examples of line integrals with varying path shapes
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Students and professionals in mathematics, physics, and engineering who are working with vector calculus and line integrals, particularly those needing to evaluate integrals over space curves.

karush
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Evaluate

$\displaystyle \int_C(x+y)ds$
where C is the straight-line segment
$x=t, y=(1-t), z=0, $
from (0,1,0) to (1,0,0)

ok this is due tuesday but i missed the lecture on it
so kinda clueless.
i am sure it is a easy one.
 
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Use $ds = \sqrt{(dx/dt)^2+(dy/dt)^2+(dz/dt)^2}dt$, take derivative of $(x(t),y(t),z(t))$ with respect to t, and then the integral goes from $(x,y,z)=(0,1,0) $ to $(1,0,0)$ check what it means for the t variable.
 

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