2(5) − cot [4 arctan 0.2 + (i/2) ln i] − 1

  • Thread starter Thread starter Jenab2
  • Start date Start date
  • Tags Tags
    Ln
AI Thread Summary
The discussion centers on the evaluation of divergent sums, particularly the sum of natural numbers, which some claim can be assigned a value of -1/12 through specific methods. Participants debate the validity of these methods, emphasizing that without clear definitions, such sums remain ill-defined. There are humorous attempts to manipulate mathematical expressions to provoke thought, illustrating the complexities of infinite series. The conversation also touches on the conceptual challenges of interpreting results that seem counterintuitive, such as obtaining a negative velocity from a sum of positive velocities. Overall, the thread highlights the nuances and playful aspects of mathematical exploration regarding divergent series.
Jenab2
Messages
85
Reaction score
22
Don't ever divide anything by the quantity in the title.

Post your favorite "fancy zeros" here.
 
Mathematics news on Phys.org
$$\frac{1}{12} + \sum _{n = 1} ^\infty n$$
 
axmls said:
$$\frac{1}{12} + \sum _{n = 1} ^\infty n$$

That should probably be

−1/12 + Σ(2,∞) 1/n⁴

Edit: whoops, no. That doesn't seem quite right, either. I evaluated ten million terms of the sum and came up with −0.0010100996222299347, so

−1/12 + 1/999 + Σ(2,∞) 1/n⁴

seems to be nearer to zero.
 
Last edited:
Jenab2 said:
That should probably be

−1/12 + Σ(2,∞) 1/n⁴

Edit: whoops, no. That doesn't seem quite right, either. I evaluated ten million terms of the sum and came up with −0.0010100996222299347, so

−1/12 + 1/999 + Σ(2,∞) 1/n⁴

seems to be nearer to zero.

Nope, it's written as I intended.
 
Unless you specify how divergent sums are to be evaluated, the formula is not well-defined.
Yes there is a specific way that leads to -1/12, but this is by far not the only way to assign finite values to divergent sums.
 
mfb said:
Unless you specify how divergent sums are to be evaluated, the formula is not well-defined.
Yes there is a specific way that leads to -1/12, but this is by far not the only way to assign finite values to divergent sums.

It was a somewhat tongue-in-cheek answer, if that wasn't clear.
 
  • Like
Likes Mentallic
I tried something like this to mess with my maths teacher in senior year once, replaced pi with some weird sums.
 
1 / Σ(1,∞) n = 0
1 / { 1/a + 1 / Σ(1,∞) n } = a, a≠0.
 
Jenab2 said:
1 / Σ(1,∞) n = 0
1 / { 1/a + 1 / Σ(1,∞) n } = a, a≠0.

See here: https://en.m.wikipedia.org/wiki/1_+_2_+_3_+_4_+_⋯

There are ways to assign a value to that sum using alternate methods. That was the "tongue-in-cheek" aspect of my response.
 
  • #10
## \begin{Vmatrix} \vec\nabla \times \vec\nabla f \end{Vmatrix} ##
 
Last edited:
  • #11
axmls said:
See here: https://en.m.wikipedia.org/wiki/1_+_2_+_3_+_4_+_⋯
There are ways to assign a value to that sum using alternate methods. That was the "tongue-in-cheek" aspect of my response.
Ah. My difficulty in appreciating the assignment was caused by my thinking of scalars in vector terms. Consider velocities in the same direction, classically being added, tail to head:

v₁ + v₂ + v₃ + v₄ + ...

where each velocity is in the direction of the +x axis and the magnitude of the velocities is proportional to the subscript.

How is it that an object, moving through an infinite succession of changes-of-velocity, all of them forward, might end up moving BACKWARD at a speed of 1/12 velocity units?

I'd figured that this was a case of getting a strange result out of an indeterminate form.
 

Similar threads

Replies
5
Views
1K
Replies
20
Views
3K
Replies
1
Views
1K
Replies
59
Views
2K
Replies
6
Views
3K
Replies
13
Views
2K
Replies
2
Views
1K
Back
Top