Neither of those is a real number, much less a positive real number.

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To find the exponential form of 1/j, it can be simplified to -j, which corresponds to e^(-j*pi/2) through Euler's identity. The magnitude of a complex number z, expressed as z = a + bj, is calculated using the formula |z| = √(a² + b²). This is derived from multiplying the complex number by its conjugate, yielding |z|² = z * z*. The discussion clarifies that the magnitude is a non-negative real number, while the square root of a complex number is more complex and can yield multiple values. Understanding these concepts is essential for working with complex numbers in mathematics.
Bob Busby
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How do you get the exponential form of 1/j? I saw a problem that says it's e^(-j*pi/2) but I have no idea where that came from.

Also, if you have a complex number, z, how do you find it's magnitude? For example, e^(j*pi*t - pi/2). In my book when they square the the magnitude of a complex number they multiply by the conjugate (e.g. |z|^2 = e^(j*pi*t - pi/2) * e^(-j*pi*t + pi/2) Why is this? Thanks for any help.
 
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For your first question, note that 1/j = -j. To get this take 1/j and multiply by j/j:
\frac{1}{j}=\frac{j}{j^2}=-j

For your second question, the definition of the magnitude of a complex number is that it is the square root of itself times its complex conjugate. To see that this corresponds to the distance from the origin when complex numbers are plotted as points in a plane, notice that if z=a+bj, then
zz*=(a+bj)(a-bj)=a2 + b2
Which is the square of the distance from the origin by the Pythagorean theorem.
 
Bob Busby said:
How do you get the exponential form of 1/j? I saw a problem that says it's e^(-j*pi/2) but I have no idea where that came from.
You could start with Euler's identity http://en.wikipedia.org/wiki/Euler's_identity:

e^{i \pi} + 1 = 0

==>

e^{i \pi} = -1

(e^{i \pi})^{1/2} = \sqrt{-1} = i

e^{i \pi/2} = i

(e^{i \pi/2})^{-1} = \frac{1}{i} = -i

e^{-i \pi/2} = -i

Alternatively you could start with Euler's formula:

e^{i\varphi} = \cos{\varphi} + i \sin{\varphi}

http://en.wikipedia.org/wiki/Euler's_formula

Now from this Wikipedia diagram of the complex plane...

220px-Euler%27s_formula.svg.png


... it can be seen that when the real part is zero, that \varphi must be \pi/2 so:

e^{i\pi/2} = \cos{(\pi/2)} + i \sin{(\pi/2)} = i

(since \cos{(\pi/2)}=0 and \sin{(\pi/2)}=1)

e^{-i\pi/2} = -i = 1/i
 
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ohhh my god... that question make me headache almost the time...:)
 
if z is a complex no...Z=X =iY then the magnitude of Z is simply =√ X+iY
 
chwala said:
if z is a complex no...Z=X =iY then the magnitude of Z is simply =√ X+iY
Completely wrong. If Z= X+iY then the magnitude of Z is the non-negative real number
\sqrt{X^2+ Y^2}

\sqrt{X+ iY}
is any of those complex numbers whose square is X+ iY

For example, if z= i= 0+ i(1) then the magnitude of z is |z|= \sqrt{1^2+ 1^2}= \sqrt{2}. But
\sqrt{z}= \sqrt{ i}= \frac{\sqrt{2}}{2}+ \frac{\sqrt{2}}{2}i
or
\sqrt{z}= \sqrt{i}= \frac{\sqrt{2}}{2}- \frac{\sqrt{2}}{2}i
 
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