2 more questions related to Circular Motion and Speed

AI Thread Summary
The discussion focuses on two physics problems related to circular motion. The first problem involves calculating the angular speed of a bicycle wheel with a diameter of 26 inches that makes 15 revolutions in 8.5 seconds, leading to an angular speed of approximately 11.1 rad/s and a distance traveled of about 94.2 feet. The second problem concerns a spool with a radius of 30 cm that wraps a wire with a diameter of 0.75 cm, requiring the calculation of the number of radians for one complete layer of wire, which totals 200.96 radians. Participants clarify the relationship between revolutions, radians, and the necessary formulas for calculating distance and speed. The conversation emphasizes the importance of understanding angular motion and its applications in real-world scenarios.
Kikki:)
Messages
17
Reaction score
0

Homework Statement


The first question reads:

In riding a bicycle, it is noted that the 26 inch diameter wheel makes 15.0 revolutions in a time of 8.50sec. What is the angular speed of the wheel? What distance does the bicycle travel during this time? (in feet) (in rad/s)


Homework Equations


Circumference = 2 pi r

360 degrees = 1 revolution

Possibly radian = arc length/radius

The Attempt at a Solution



I do know that the radius in feet is 1.1ft and the diameter is 2.2ft. I also figured out that the amount of rads is 6.9rad by: 1.1rev. x 2pi rad/rev = 6.9 rad (the revs cancel out). But would you use one of the kinematic equations to find for the distance and speed? I get that you would probably use the fomula for average velocity = change in distance over change in time.

The second question:

Homework Statement



An electrical wire with a diameter of 0.75cm is wound on a spool with a radius of 30cm and a length of 24cm. Through how many radians must the spool be turned to wrap one even layer of wire? What is the length of this wound wire?

Homework Equations



C = 2 pi r


The Attempt at a Solution



I first drew it all out. then took 24cm divided by .75cm to equal 32cm. Is that how you find the length of the wire? I'm not exactly getting how to do this problem at all. Would finding the circumference of both be a good thing?
 
Physics news on Phys.org
I do know that the radius in feet is 1.1ft and the diameter is 2.2ft. I also figured out that the amount of rads is 6.9rad by: 1.1rev. x 2pi rad/rev = 6.9 rad (the revs cancel out).

Where did you get 1.1rev from? The question says that the wheel turned through 15 revolutions.

But would you use one of the kinematic equations to find for the distance and speed? I get that you would probably use the fomula for average velocity = change in distance over change in time.

Angular speed is just the angle divided by time, exactly analogous to how linear speed is linear distance divided by time. So however many radians 15 revolutions is, that value divided by 8.5s gives you the angular speed.

As for distance traveled, how far does the bike travel for each revolution of its wheels?

Is that how you find the length of the wire? I'm not exactly getting how to do this problem at all. Would finding the circumference of both be a good thing?

You've already found that the wire must be wrapped around the spool 32 times. How many radians does this correspond to? How much wire is needed to wrap around the spool once?
 
ideasrule said:
Where did you get 1.1rev from? The question says that the wheel turned through 15 revolutions.



Angular speed is just the angle divided by time, exactly analogous to how linear speed is linear distance divided by time. So however many radians 15 revolutions is, that value divided by 8.5s gives you the angular speed.

As for distance traveled, how far does the bike travel for each revolution of its wheels?



You've already found that the wire must be wrapped around the spool 32 times. How many radians does this correspond to? How much wire is needed to wrap around the spool once?

So take 15 rev x 2 x pi rad/rev = 94.2 rads. Then take 94.2rad divided by 8.5s = 11.1 rad/s.

Then for the distance you would take 11.1rads/s divided by 1.1ft.\alpha = a/r formula. Or would you use \omega = v/r ?

Since it was 32times to wrap it around to convert it to rads you take 32 x 2pi/rads = 200.96rads. But its asking to find it just for once around, so you take 200.96 divided by 60 to get 3.35rads? But for to finds the length of this wire you take the 3.35rads x 30cm = 100.5cm
 
Much thanks for helping me figure it out! :]
 
Thread 'Collision of a bullet on a rod-string system: query'
In this question, I have a question. I am NOT trying to solve it, but it is just a conceptual question. Consider the point on the rod, which connects the string and the rod. My question: just before and after the collision, is ANGULAR momentum CONSERVED about this point? Lets call the point which connects the string and rod as P. Why am I asking this? : it is clear from the scenario that the point of concern, which connects the string and the rod, moves in a circular path due to the string...
Back
Top