2 objects connected by a spring - Minimum Force required to move the objects

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The discussion centers on calculating the minimum force required to move two objects connected by a spring, emphasizing the forces of friction and tension. The proposed solution suggests that the force needed is F = kg(m1 + 0.5 m2), but this is contested due to assumptions about the spring's initial state and the nature of the applied force. It is argued that the spring may not be initially relaxed and that allowing the force to change signs could yield better results. Additionally, concerns are raised about the static and kinetic coefficients of friction not being specified. Overall, the conversation highlights complexities in the dynamics of the system and the assumptions underlying the calculations.
EEristavi
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Homework Statement
2 objects with masses m1 and m2 are connected by spring. The kinetic friction coefficient (Between objects and surface) is k. We apply horizontal force - F on object 1 and object 2 starts to move.
What is the Minimum Value of F.
Relevant Equations
Newton's Second Law
On object 2: There are only 2 horizontal forces - Friction and Tension (of the spring).
T = km2g

On Object 1: There are 3 horizontal forces and the minimum value for F is when:
F - km1g - km2g = 0
F = kg(m1 + m2)

However, Solution is:
F = kg(m1 + 0.5 m2)

Any opinion?
 
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EEristavi said:
However, Solution is:
F = kg(m1 + 0.5 m2)
I believe that they are contemplating a solution where the spring between the masses is initially relaxed. A fixed force is applied to ##m_1## and it begins to move under this force at an acceleration that decreases over time as the spring is stretched. Eventually (at a spring force of 0.5 gkm), the acceleration ceases and decelleration ensues. Eventually (at a spring force of 1.0 gkm) ##m_1## comes to a stop with ##m_2## on the verge of slipping.

The provided solution is arguably incorrect, however. First, because it depends on the unstated assumption that the spring is initially relaxed. Second, because better strategies are available if the delivered force is allowed to change signs within the maximum magnitude imposed by F.

Edit: Or to be a complete jerk, one could say that there is no minimum. A force of ##-\infty## will do just fine and is way less than ##kg(m_1 + 0.5 m_2)##.
 
jbriggs444 said:
Edit: Or to be a complete jerk, one could say that there is no minimum. A force of −∞−∞-\infty will do just fine and is way less than kg(m1+0.5m2)

Nice one :D
 
jbriggs444 said:
First, because it depends on the unstated assumption that the spring is initially relaxed. Second, because better strategies are available if the delivered force is allowed to change signs within the maximum magnitude imposed by F.
Third, because we are not told that the static coefficient does not exceed the kinetic.

With regard to varying F, what if F is a constant vector, but necessarily collinear with the separation of the masses? Looks tricky.

Edit: I meant not necessarily.
 
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haruspex said:
Third, because we are not told that the static coefficient does not exceed the kinetic.

With regard to varying F, what if F is a constant vector, but necessarily collinear with the separation of the masses? Looks tricky.
Ahh yes. A two-dimensional surface. Very nice.
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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