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manderzz

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Okay, so I did a lab where we had a 2 pulley system that involved a string and three masses. The string is set up so it is in the shape of an m when put on the pulleys. The known mass is put on the middle string (m3) hanging down and the two outside masses (m1) and (m2) are unknown and are not equal to each other. The middle mass is .200 kg. The angle between T1 and T2 is 80 deg the angle between T1 and T3 is 150 deg and the angle between T2 and T3 is 130 deg. I need to find M1 and M2. I drew a fbd and know that T1y and T2y must be equal to the magnitude of T3. Thank you in advance.

T1cosθ+T2cosθ+T3=0

I have been trying to work with my free body diagram to figure out the T1y and T2y values by using Pythagoras. I know that the middle mass has a weight of (9.8)(.200 kg)=1.96 N. So the T1y and T2y need to add up to equal this. I have no idea where to start, any help would be so appreciated!!

T1cosθ+T2cosθ+T3=0

I have been trying to work with my free body diagram to figure out the T1y and T2y values by using Pythagoras. I know that the middle mass has a weight of (9.8)(.200 kg)=1.96 N. So the T1y and T2y need to add up to equal this. I have no idea where to start, any help would be so appreciated!!

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