2017 times a is a natural number

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The discussion revolves around finding the value of 2017 times A, where A is defined as a series involving the sum of reciprocals of cumulative sums. Participants suggest using summation notation and recognizing patterns in the series to simplify calculations. There is an emphasis on identifying the nth term and applying partial fraction decomposition to facilitate computation. Additionally, the importance of the formula for the sum of the first k natural numbers is highlighted as a useful tool for solving the problem. Overall, the conversation focuses on strategies for approaching the calculation of A and its relation to 2017.
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Homework Statement



category=5.png

find 2017 times A

Homework Equations

The Attempt at a Solution


the sum of last members denominator.is 2017 multiplied by 1008
the member before it is 2015 multiplied by 1008
before it 2015 times 1007
2013 times 1007
2013 times 2016
how can i move futher
 
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Have you tried to write this equation in summation notation? The denominators can be written in a closed form, which the inverse can be taken of.
 
giokrutoi said:

Homework Statement



category=5.png

find 2017 times A

Homework Equations

The Attempt at a Solution


the sum of last members denominator.is 2017 multiplied by 1008
the member before it is 2015 multiplied by 1008
before it 2015 times 1007
2013 times 1007
2013 times 2016
how can i move futher
$$A = {1 \over 1+ 2} + {1 \over 1+ 2 +3 } +\cdots + {1 \over 1+ 2+ \cdots +2016}$$
$$\color {red}{A + 1 = {1\over 1} + {1 \over 1+ 2} + {1 \over 1+ 2 +3 } +\cdots + {1 \over 1+ 2+ \cdots +2016}+ \cdots }$$

Find the nth term of 'red thing', then do partial fraction decomposition. You will a series that is very easy to compute.
 
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giokrutoi said:
how can i move futher
A good first step is to try to spot the pattern. With just one term, it is 1/3. What is the sum of the first two? Of the first three?...
 
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Haruspex has a good hint. A related hint is "about how big do you expect your answer to be?"
 
Just one reminder, I guess you have been taught that ##1+2+...+k=\frac{k(k+1)}{2}##, because it should be easy to recognize that, but you don't even mention it in your post or at relevant equations.
 
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I picked up this problem from the Schaum's series book titled "College Mathematics" by Ayres/Schmidt. It is a solved problem in the book. But what surprised me was that the solution to this problem was given in one line without any explanation. I could, therefore, not understand how the given one-line solution was reached. The one-line solution in the book says: The equation is ##x \cos{\omega} +y \sin{\omega} - 5 = 0##, ##\omega## being the parameter. From my side, the only thing I could...
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