3 identical springs hanging from ceiling

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SUMMARY

The discussion focuses on calculating the spring constant and the weight of an unknown object using three identical massless springs. The correct approach involves applying Hooke's Law, where the spring constant (k) is determined using the displacement of the springs when weights are applied. The correct spring constant for the springs is 14 N/m, derived from the second spring's displacement of 0.3 m. The weight of the unknown object is calculated to be 18.64 N based on the established spring constant.

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  • Understanding of Hooke's Law (k = mg/x)
  • Basic principles of static equilibrium
  • Knowledge of mass and weight relationships
  • Familiarity with spring mechanics
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I got the following problem wrong, and don't know why, so hopefully somebody would be able to help me out!

Three identical (massless) springs are hung from the ceiling.
Spring 1: Nothing hung from spring. The spring's bottom is 0.2 m below the ceiling.
Spring 2: A 7 N object is hung from the spring. The spring's bottom is 0.5 m below the ceiling.
Spring 3: An object of unknown weight is hung from the spring. The spring's bottom is 1 m below the ceiling.

a. Find the spring constant that each spring has.
b. Find the weight of the unknown object.

For A, I used k = 4pi^2(0.7143)/1. I got 0.7143 as my mass by using F=ma, and I used 1 for T, since no time or frequency was given for either of the 3 springs. I guess since part A was wrong, that answer led to my answer for part B to be wrong also.
 
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FlipStyle1308 said:
I got the following problem wrong, and don't know why, so hopefully somebody would be able to help me out!

Three identical (massless) springs are hung from the ceiling.
Spring 1: Nothing hung from spring. The spring's bottom is 0.2 m below the ceiling.
Spring 2: A 7 N object is hung from the spring. The spring's bottom is 0.5 m below the ceiling.
Spring 3: An object of unknown weight is hung from the spring. The spring's bottom is 1 m below the ceiling.

a. Find the spring constant that each spring has.
b. Find the weight of the unknown object.

For A, I used k = 4pi^2(0.7143)/1. I got 0.7143 as my mass by using F=ma, and I used 1 for T, since no time or frequency was given for either of the 3 springs. I guess since part A was wrong, that answer led to my answer for part B to be wrong also.
You are using the wrong equation. That equation can only be used when the mass is oscillating!

And I have no idea how you got your mass!

No, use that at equilibrium, k x = mg. You then find the spring constant from spring 2. Since they are identical, they all have the same k.
Now use that equation again to find the mass for spring 3 (the answer will be obvious)
 
I got the same answer I had before. 14? Or should it be -14?
 
FlipStyle1308 said:
I got the same answer I had before. 14? Or should it be -14?
14 N/m is the correct answer (k is never negative). Are you saying this is the wrong answer?

EDIT: Wait, I had not noticed the 0.2 meter of spring 1. So you must use a distance of 0.3 m, not 0.5m in the equation!
 
Oh, so it's the distance below the original location of the spring without a mass?
 
FlipStyle1308 said:
Oh, so it's the distance below the original location of the spring without a mass?
Yes. In the equation kx = mg, the x represents the *extra stretch* of the spring when the mass is attached as compared to when there was no mass at all.
 
So 23.3 = k, and the weight of the unknown object is 18.64?
 
Never mind, it's correct, thanks!
 

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