3 Phase Machine Line Current problem

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SUMMARY

The discussion centers on calculating the line current for a 415V, 50Hz, 3-phase supply connected to a 10kW load with a power factor of 0.8 lagging. The correct line current is determined to be 17.39 Amps. The calculations utilize the formula P = VICos(power factor) and the relationship between line-to-line voltage and phase voltage, specifically Vφ = VLL/√3. The confusion regarding the use of cos(angle) versus cos(power factor) is clarified, emphasizing the importance of using the correct terminology in electrical calculations.

PREREQUISITES
  • Understanding of 3-phase electrical systems
  • Knowledge of power factor and its implications
  • Familiarity with electrical formulas, specifically P = VICos(power factor)
  • Basic concepts of star and delta connections in electrical circuits
NEXT STEPS
  • Study the calculation of line and phase currents in 3-phase systems
  • Learn about the implications of power factor in electrical systems
  • Explore the differences between star and delta configurations in 3-phase circuits
  • Investigate the use of power factor correction techniques in electrical engineering
USEFUL FOR

Electrical engineering students, professionals working with 3-phase systems, and anyone involved in power calculations and electrical load analysis.

AdamBG10
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Hi guys,

I would really appreciate some help with this problem(probably quite easy for anybody with Electrical Engineering experience).

Thanks in advance

Homework Statement



A 415V, 50Hz, 3-phase supply is connected to a 3 phase load of 10kw with a power factor of 0.8 lagging. Find the magnitude of the line currents.

Homework Equations



P = VICos(power factor)

Total Power = 3 V(p)I(p)cos(power factor)

The Attempt at a Solution



Attempted the question using the equations above, except I obtained the wrong answer.

Correct answer = 17.39Amps
 
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Assuming the 415V is line to line rms and that the 10kW is the total wattage for all three phases:

V_{\phi}=\frac{V_{LL}}{\sqrt{3}}
with V_{\phi} being a per phase voltage and V_{LL} being the line-to-line voltage.

Next, we know that:
P_{3\phi} = 3V_{\phi}I_{\phi}PF
with PF = powerfactor. And if this is star connected...
I_{\phi}=I_{LL}

so
P_{3\phi}=3\frac{V_{LL}}{\sqrt{3}}I_{LL}PF=\sqrt{3}V_{LL}I_{LL}PF
or
I_{LL}=\frac{P_{3\phi}}{V_{LL}\sqrt{3}PF}

You seem to be confusing something. cos(angle) = PF. You don't say cos(PF). As far as I know, cos(PF) means nothing of importance.
 
xcvxcvvc said:
Assuming the 415V is line to line rms and that the 10kW is the total wattage for all three phases:

V_{\phi}=\frac{V_{LL}}{\sqrt{3}}
with V_{\phi} being a per phase voltage and V_{LL} being the line-to-line voltage.

Next, we know that:
P_{3\phi} = 3V_{\phi}I_{\phi}PF
with PF = powerfactor. And if this is star connected...
I_{\phi}=I_{LL}

so
P_{3\phi}=3\frac{V_{LL}}{\sqrt{3}}I_{LL}PF=\sqrt{3}V_{LL}I_{LL}PF
or
I_{LL}=\frac{P_{3\phi}}{V_{LL}\sqrt{3}PF}

You seem to be confusing something. cos(angle) = PF. You don't say cos(PF). As far as I know, cos(PF) means nothing of importance.

Thanks very much!
 

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