3rd order homogeneous Linear ODE matrix transformation-how to write the answer

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The discussion focuses on transforming a 3rd order homogeneous linear ordinary differential equation (ODE) into matrix notation. The equation y''' + 7y'' + 6y' + 3y = 0 is converted into a system of first-order ODEs using the vector x = [x_1, x_2, x_3]^T, where x_1 = y, x_2 = y', and x_3 = y''. The resulting matrix form is x' = A x, with A being a specific matrix derived from the coefficients of the ODE. Participants clarify that while the transformation is correct, the full solution requires expressing all first-order equations, not just one. The matrix approach is necessary as it aligns with the problem's requirements for a systematic solution.
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3rd order homogeneous Linear ODE matrix transformation---how to write the answer

Homework Statement



Transform this 3rd order homogeneous linear ODE with constant coefficients using matrix notation.
<br /> y&#039;&#039;&#039;+7y&#039;&#039;+6y&#039;+3y=0<br />

Homework Equations


The Attempt at a Solution


My answer is
x&#039;=AX
x=[x_1,x_2,x_3]^T
A=Mat[[1,0,0][0,1,0][-7,-6,-3]]

x'=
(x_1)
(x_2)
(-7x_1-6x_2-3x_3)

My question is do I leave in this form and also is it correct?

Thanks
 
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i would strongly advise you to write out precisely what substitutions you are making. It will make it much easier for all, including yourself, to see what you are doing and whether or not it is correct (not to mention shock and amaze your teacher!).

You appear to be saying that
x= \begin{bmatrix}x_1 \\ x_2\\ x_3\end{bmatrix}
where
x_1= y, x_2= y&#039;, and x_3= y&#039;&#039;.

Then the given equation becomes x_3&#039;+ 7x_3+ 6x_2+ 3x_1= 0 which is the same as x_3&#039;= -3x_1- 6x_2- 7x_3.
Of course, you also have x_1&#039;= x_2 and x_2&#039;= x_3 so your equation, in matrix form, is
x&#039;= \begin{bmatrix}x_1&#039; \\ x_2&#039; \\ x_3&#039;\end{bmatrix}= \begin{bmatrix}0 &amp; 1 &amp; 0 \\ 0 &amp; 0 &amp; 1 \\ -3 &amp; -6 &amp; -7\end{bmatrix}\begin{bmatrix}x_1 \\ x_2 \\ x_3 \end{bmatrix}

which is, I believe, what you have.
 


Yes that's exactly what I meant. Sorry for the illegible post, I didn't know the LaTex for Matrices. How would you advice me to write the answer? I have posted what your final matrix equation comes out to: 3rd row: -7x_1-6x_2-3x_3
which I think would go back to y=-7y-6y&#039;-3y&#039;&#039;?Thanks
 


Hi again HallsofIvy, one simple question, Is my solution to this ODE <br /> x_3&#039;= -3x_1- 6x_2- 7x_3<br />. if so why did I need matrices and what use is that?? I also forgot the final bit of the question.
Question:
Transform this 3rd order homogeneous linear ODE with constant coefficients using matrix notation.
ODE
into a system of first oder ODE's.

Have I done this?

Thanks
 


pat666 said:
Hi again HallsofIvy, one simple question, Is my solution to this ODE <br /> x_3&#039;= -3x_1- 6x_2- 7x_3<br />. if so why did I need matrices and what use is that?? I also forgot the final bit of the question.
Question:
Transform this 3rd order homogeneous linear ODE with constant coefficients using matrix notation.
ODE
into a system of first oder ODE's.

Have I done this?

Thanks
First, that's not a solution to the differential equation though it is a (partial) solution to the question asked. However, just saying "x_3&#039;= -3x_1- 6x_2- 7x_3" is not the entire solution because it does not give the important equations for x_1 and x_2.

You "need" the matrix equations because that was what the problem told you to do!

Yes, converting to a system of first order equations would be: x_1&#039;= x_2, x_2&#039;= x_3, and x_3&#039;= -3x_1- 6x_2-7x_3.
 


So I was not actually looking for a "solution" to this ODE?

Thanks HoI
 
Question: A clock's minute hand has length 4 and its hour hand has length 3. What is the distance between the tips at the moment when it is increasing most rapidly?(Putnam Exam Question) Answer: Making assumption that both the hands moves at constant angular velocities, the answer is ## \sqrt{7} .## But don't you think this assumption is somewhat doubtful and wrong?

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