5.76x10^-3 NRadiation Force on Echo II Satellite Ballon

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Homework Help Overview

The problem involves calculating the force exerted by solar radiation on the Echo II satellite, which is modeled as a spherical shell. The context includes parameters such as the intensity of solar radiation, the dimensions of the satellite, and the materials involved.

Discussion Character

  • Conceptual clarification, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the calculation of the effective area for radiation pressure, questioning the use of 4πr² versus πr². There is also consideration of the perpendicular component of radiation impacting the spherical shell.

Discussion Status

The discussion is exploring different interpretations of the effective area and the assumptions regarding the directionality of radiation. Participants are providing insights into the reasoning behind their calculations and questioning the appropriateness of certain approaches without reaching a consensus.

Contextual Notes

Participants note that the radiation's effect may not be independent of the satellite's mass, and there are considerations regarding the geometry of the situation that may affect the calculations.

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Homework Statement



The intensity of the suns' radiation just outside the Earth's atmosphere is approximately
8x10^4 joules/m^2*min
Approximately what force does this radiation exert on the Echo II reflecting satellite ballon? Echo II is a spherical shell of radius 20.4 m. Its skins consists of a layer of Mylar plastic, 9x10^-6 m thick, between two layers of aluminum, each 4.5x10^-6 m thick. The density of Mylar is 10^3 kg/m^3; of aluminum 2.7x10^3 kg/m^3..

This is problem 1-2 out of Special Relativity by A.P. French and the solution is 5.76x10^-3 N

Also the information on the densities are for the preceding question about the gravitational pull on the shell. I assume the force the radation exerts is independent of its mass.

Homework Equations



The Attempt at a Solution



8x10^4 joules/m^2*min / 60 = 1333 joules/m^2*sec
1333 joules/m^2*sec * 4(pi)(20.4m)^2 = 6972827.7 joules/sec

Here is where things break down. I tried dividing by the speed of light

(6972827.7 joules/sec) / (3*10^8 m/sec) = .0232426 N
 
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the effective area is not 4(pi)(20.4m)^2, only (pi)(20.4m)^2
 
why do you use [tex]4 \pi r^2[/tex] for the area? That is the area of the entire surface of the balloon. Dividing by the speed of light is Ok, since the energy of a photon is cp.
(with p the momentum).
 
This is probably extremely intuitive, but why is it not 4(pi)r^2 or even 2(pi)r^2 since only half would be exposed?
 
the radiation is not perpendicular to all parts of the spherical shell and we only need the perpendicular component of radiation. This is something like the electric flux when using Gauss theorem in electrostatics. Suppose there's a uniform electric field, what is the flux passing through a sphere with radius R in the field? the answer is E*pi*R^2, not E*4pi*R^2, or E*2pi*R^2.
 

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